Write an equation for a line that passes through (-4, 2) and perpendicular to the line whose equation is y = –+7 %3D 3x

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I've been having trouble with two of these problems ! Thank you for the help in advance ! A real life saver !  I have provided an image also of the questions . 

#8 write an equation for a line that passes through (-4,2) and perpendicular to the line whose equation is y=1/3x+7 

 

#22 Write an equation in slope intercept form of a linear function F such that the graph of f passes through (-5,6) and is perpendicular to the line that has an x- intercept of 3 and y intercept of -9 

### Problem Set 3
**Math1314**

**Section 2.4 and 2.5**

---

#### 2.4 #8
**Problem Statement:**
Write an equation for a line that passes through (-4, 2) and is perpendicular to the line whose equation is \( y = \frac{1}{3}x + 7 \).

---

#### 2.4 #22
**Problem Statement:**
Write an equation in slope-intercept form of a linear function \(f\) such that the graph of \(f\) passes through (-5, 6) and is perpendicular to the line that has an x-intercept of 3 and a y-intercept of -9.

---

### Explanation of Concepts:

In these problems, you are required to use the concept of perpendicular lines and their slopes. When two lines are perpendicular, the slope of one line is the negative reciprocal of the slope of the other line.

For Problem 2.4 #8:
- The given line has a slope of \( \frac{1}{3} \).
- The slope of the line perpendicular to this line will be \( -3 \) (negative reciprocal of \( \frac{1}{3} \)).
- You need to use the point-slope form of the equation of a line to find the equation passing through (-4, 2).

For Problem 2.4 #22:
- First, determine the slope of the line with an x-intercept of 3 and a y-intercept of -9.
- Use the slope-intercept form \( y = mx + b \) where \( m \) is the slope.
- Find the slope using the points (3, 0) and (0, -9).
- Then, find the perpendicular slope.
- Using the point (-5, 6), apply the new slope to find the equation of the line in slope-intercept form.

Understanding these principles is key to solving these problems correctly.
Transcribed Image Text:### Problem Set 3 **Math1314** **Section 2.4 and 2.5** --- #### 2.4 #8 **Problem Statement:** Write an equation for a line that passes through (-4, 2) and is perpendicular to the line whose equation is \( y = \frac{1}{3}x + 7 \). --- #### 2.4 #22 **Problem Statement:** Write an equation in slope-intercept form of a linear function \(f\) such that the graph of \(f\) passes through (-5, 6) and is perpendicular to the line that has an x-intercept of 3 and a y-intercept of -9. --- ### Explanation of Concepts: In these problems, you are required to use the concept of perpendicular lines and their slopes. When two lines are perpendicular, the slope of one line is the negative reciprocal of the slope of the other line. For Problem 2.4 #8: - The given line has a slope of \( \frac{1}{3} \). - The slope of the line perpendicular to this line will be \( -3 \) (negative reciprocal of \( \frac{1}{3} \)). - You need to use the point-slope form of the equation of a line to find the equation passing through (-4, 2). For Problem 2.4 #22: - First, determine the slope of the line with an x-intercept of 3 and a y-intercept of -9. - Use the slope-intercept form \( y = mx + b \) where \( m \) is the slope. - Find the slope using the points (3, 0) and (0, -9). - Then, find the perpendicular slope. - Using the point (-5, 6), apply the new slope to find the equation of the line in slope-intercept form. Understanding these principles is key to solving these problems correctly.
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