Answered: Write an application that accepts up to…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Question

This is the question I am stuck on -

Write an application that accepts up to 20 Strings, or fewer if the user enters the terminating value ZZZ. Store each String in one of two lists—one list for short Strings that are 10 characters or fewer and another list for long Strings that are 11 characters or more. After data entry is complete, prompt the user to enter which type of String to display, and then output the correct list.

For this exercise, you can assume that if the user does not request the list of short strings, the user wants the list of long strings. If a requested list has no Strings, output The list is empty. Prompt the user continuously until a sentinel value, ZZZ, is entered.

This is the code I have but I am not getting any checks correct with it -

import java.util.Scanner;

public class CategorizeStrings {

public static void main(String[] args) {

int SIZE = 20;

String[] sStrings = new String[SIZE];

String[] lStrings = new String[SIZE];

String s;

int sCounter = 0, lCounter = 0;

Scanner sc = new Scanner(System.in);

for (int i = 0; i < SIZE; i++) {

System.out.print("Enter a string : ");

s = sc.nextLine();

if (s.equalsIgnoreCase("zzz")) { // checking for sentinal value

break;

} else {

if (s.length() <= 10) // if short string

sStrings[sCounter++] = s;

else // if long string

lStrings[lCounter++] = s;

}

} // end of for

System.out.println("\n\n1.Display Short strings\n2.Display Long Strings\nEnter choice : ");

int choice = sc.nextInt();

if (choice == 1) {

if (sCounter == 0) {

System.out.println("The list is empty");

} else {

for (int i = 0; i < sCounter; i++) {

System.out.println(sStrings[i]);

}

} else if (choice == 2) {

if (lCounter == 0) {

System.out.println("The list is empty");

} else {

for (int i = 0; i < lCounter; i++) {

System.out.println(lStrings[i]);

}

} else {

System.out.println("Invalid Choice");

}

Here is an example of one of the checks I a,m gettign wrong -

Test Case Incomplete

Categorize Strings A B C D, 3 idioms

Input

A penny for your thoughts

Barking up the wrong tree

Curiosity killed the cat

ZZZ

Output

Enter a string : A

Enter a string : B

Enter a string : C

Enter a string : D

Enter a string : A penny for your thoughts

Enter a string : Barking up the wrong tree

Enter a string : Curiosity killed the cat

Enter a string : ZZZ

1.Display Short strings

2.Display Long Strings

Enter choice :

Exception in thread "main" java.util.InputMismatchException at java.util.Scanner.throwFor(Scanner.java:864) at java.util.Scanner.next(Scanner.java:1485) at java.util.Scanner.nextInt(Scanner.java:2117) at java.util.Scanner.nextInt(Scanner.java:2076) at CategorizeStrings.main(CategorizeStrings.java:45)

ZZZ

Results(all are marked in red for being wrong/incorrect)

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions