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Write a Python program that asks the user for quantity and takes some marks out of 100 as input. Valid marks are 0 to 100. However, due to user error, some marks may fall outside that range, say 101 or -5 (minus five). Print average of valid marks and percentage of invalid marks (Error Rate). Assume there is at least one valid mark and at least one invalid mark.

Write a Python program that asks the user for quantity and takes some marks out of 100 as input. Valid marks are 0 to 100. However, due to user error, some marks may fall outside that range, say 101 or -5 (minus five). Print average of valid marks and percentage of invalid marks (Error Rate). Assume there is at least one valid mark and at least one invalid mark.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Must show it in Python:

Please show step by step with comments.

Please show it in simplest form.

Please don't use any functions

Please don't use any def func ()

Sample Input 2: 3 500 100 Sample Output 2: Average: 51.5 Error Rate (%): 33.33333333333333 Explanation 2: 3 means there are 3 inputs. Average of valid marks is (3+100)/2 = 103/2 = 51.5 500 is invalid. So, there is 1 number out of 3 that is invalid. Hence the percentage = 1/3x100 = 33.33333333333333
Transcribed Image Text:Sample Input 2: 3 500 100 Sample Output 2: Average: 51.5 Error Rate (%): 33.33333333333333 Explanation 2: 3 means there are 3 inputs. Average of valid marks is (3+100)/2 = 103/2 = 51.5 500 is invalid. So, there is 1 number out of 3 that is invalid. Hence the percentage = 1/3x100 = 33.33333333333333
Question: Write a Python program that asks the user for quantity and takes some marks out of 100 as input. Valid marks are 0 to 100. However, due to user error, some marks may fall outside that range, say 101 or -5 (minus five). Print average of valid marks and percentage of invalid marks (Error Rate). Assume there is at least one valid mark and at least one invalid mark. Sample Input 1: 5 20 -3 105 70 100 Sample Output 1: Average: 63.333333333333336 Error Rate (%): 40.0 Explanation 1: 5 means there are 5 inputs. Average of valid marks is (20+70+100)/3 =190/3 = 63.333333333333336 -3 and 105 are invalid. So, there are 2 numbers out of 5 that are invalid. Hence the percentage = 2/5x100 = 40.0 %3D
Transcribed Image Text:Question: Write a Python program that asks the user for quantity and takes some marks out of 100 as input. Valid marks are 0 to 100. However, due to user error, some marks may fall outside that range, say 101 or -5 (minus five). Print average of valid marks and percentage of invalid marks (Error Rate). Assume there is at least one valid mark and at least one invalid mark. Sample Input 1: 5 20 -3 105 70 100 Sample Output 1: Average: 63.333333333333336 Error Rate (%): 40.0 Explanation 1: 5 means there are 5 inputs. Average of valid marks is (20+70+100)/3 =190/3 = 63.333333333333336 -3 and 105 are invalid. So, there are 2 numbers out of 5 that are invalid. Hence the percentage = 2/5x100 = 40.0 %3D
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