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Write a program to evaluate an expression entered in "postfix" form using the stack concept. Assume: The operators in the expression will not be other than '+',","" ,or ". The class Postfix has the following method. Method Name Method Description This method accepts a string as an expression from the Main method, evaluates the string in the "postfix" form. public double evaluate(string exp) It returns the double value obtained after evaluated in “postfix" form. [Note: The method should be invoked through the main function.] Sample Input and Output: [ All text in bold corresponds to input and the rest corresponds to output ] Enter postfix expression to be evaluated: 13+ Result is :4 Explanation: First number is 1 Second number is 3 Operator is + So in postfix form, it is evaluated as 1+3 = 4

Write a program to evaluate an expression entered in "postfix" form using the stack concept. Assume: The operators in the expression will not be other than '+',","" ,or ". The class Postfix has the following method. Method Name Method Description This method accepts a string as an expression from the Main method, evaluates the string in the "postfix" form. public double evaluate(string exp) It returns the double value obtained after evaluated in “postfix" form. [Note: The method should be invoked through the main function.] Sample Input and Output: [ All text in bold corresponds to input and the rest corresponds to output ] Enter postfix expression to be evaluated: 13+ Result is :4 Explanation: First number is 1 Second number is 3 Operator is + So in postfix form, it is evaluated as 1+3 = 4

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question Provided In The Attachment.

USE C++ LANGUAGE. MATCH OUTPUT AS IT IS.

 

STRICTLY USE THE BELOW TEMPLATE WHEN MAKING A SOLUTION.

---------------------------------------------------------

main.cpp

#include<cstring>
#include<iostream>
#include<string>
#include "Postfix.cpp"
using namespace std;
int main()
{
//Fill your code here
}

 

postfix.cpp

#include <bits/stdc++.h>
using namespace std;

class Postfix {

public:

double evaluate(string exp){
//Fill your code here
}
};
Write a program to evaluate an expression entered in “postfix" form using the stack concept. Assume: The operators in the expression will not be other than '+',",*",or ". The class Postfix has the following method. Method Description This method accepts a string as an expression from the Main method, evaluates the string in the "postfix" form. Method Name public double evaluate(string exp) It returns the double value obtained after evaluated in "postfix" form. [Note: The method should be invoked through the main function.] Sample Input and Output: [ All text in bold corresponds to input and the rest corresponds to output] Enter postfix expression to be evaluated: 13+ Result is :4 Explanation: First number is 1 Second number is 3 Operator is + So in postfix form, it is evaluated as 1+3 = 4
Transcribed Image Text:Write a program to evaluate an expression entered in “postfix" form using the stack concept. Assume: The operators in the expression will not be other than '+',",*",or ". The class Postfix has the following method. Method Description This method accepts a string as an expression from the Main method, evaluates the string in the "postfix" form. Method Name public double evaluate(string exp) It returns the double value obtained after evaluated in "postfix" form. [Note: The method should be invoked through the main function.] Sample Input and Output: [ All text in bold corresponds to input and the rest corresponds to output] Enter postfix expression to be evaluated: 13+ Result is :4 Explanation: First number is 1 Second number is 3 Operator is + So in postfix form, it is evaluated as 1+3 = 4
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