Write a polynomial f (x) that satisfies the given conditions. Polynomial of lowest degree with zeros of - 4 (multiplicity 2), 1 (multiplicity 1), and with f (0) = 96. f (x) =

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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem Statement:**

Write a polynomial \( f(x) \) that satisfies the given conditions.

1. Polynomial of lowest degree with zeros of \( -4 \) (multiplicity 2) and \( 1 \) (multiplicity 1).
2. The function is such that \( f(0) = 96 \).

**Solution:**

To define the polynomial \( f(x) \), we start by expressing it in terms of its roots:

- The root \( -4 \) with multiplicity 2 implies a factor of \( (x + 4)^2 \).
- The root \( 1 \) with multiplicity 1 implies a factor of \( (x - 1) \).

Thus, the polynomial can be expressed as:

\[ f(x) = a(x + 4)^2(x - 1) \]

where \( a \) is a constant to be determined.

To find \( a \), we use the condition \( f(0) = 96 \):

\[ f(0) = a(0 + 4)^2(0 - 1) = 96 \]
\[ a \cdot 16 \cdot (-1) = 96 \]
\[ a \cdot (-16) = 96 \]
\[ a = \frac{96}{-16} \]
\[ a = -6 \]

Therefore, the polynomial is:

\[ f(x) = -6(x + 4)^2(x - 1) \]
Transcribed Image Text:**Problem Statement:** Write a polynomial \( f(x) \) that satisfies the given conditions. 1. Polynomial of lowest degree with zeros of \( -4 \) (multiplicity 2) and \( 1 \) (multiplicity 1). 2. The function is such that \( f(0) = 96 \). **Solution:** To define the polynomial \( f(x) \), we start by expressing it in terms of its roots: - The root \( -4 \) with multiplicity 2 implies a factor of \( (x + 4)^2 \). - The root \( 1 \) with multiplicity 1 implies a factor of \( (x - 1) \). Thus, the polynomial can be expressed as: \[ f(x) = a(x + 4)^2(x - 1) \] where \( a \) is a constant to be determined. To find \( a \), we use the condition \( f(0) = 96 \): \[ f(0) = a(0 + 4)^2(0 - 1) = 96 \] \[ a \cdot 16 \cdot (-1) = 96 \] \[ a \cdot (-16) = 96 \] \[ a = \frac{96}{-16} \] \[ a = -6 \] Therefore, the polynomial is: \[ f(x) = -6(x + 4)^2(x - 1) \]
**Problem Statement**

Write a polynomial \( f(x) \) that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient.

Polynomial of lowest degree with lowest possible integer coefficients and zeros of \( 2i \) and \( 2 - i \).

**Function**

\[ f(x) = \boxed{} \]

**Instructions for Solving**

To find the polynomial \( f(x) \):

1. Note the given zeros \( 2i \) and \( 2 - i \).
2. Remember that complex roots occur in conjugate pairs in polynomials with real coefficients. Thus, the zeros are \( 2i, -2i, 2 - i, \) and \( 2 + i \).
3. Construct factors from these zeros: 
   - \( (x - 2i) \)
   - \( (x + 2i) \)
   - \( (x - (2 - i)) \)
   - \( (x - (2 + i)) \)
4. Multiply the factors to form the polynomial using the identity \( (x-a)(x+a) = x^2-a^2 \) for complex conjugates.

Using these steps, you will have the polynomial expression with the lowest degree and integer coefficients.
Transcribed Image Text:**Problem Statement** Write a polynomial \( f(x) \) that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient. Polynomial of lowest degree with lowest possible integer coefficients and zeros of \( 2i \) and \( 2 - i \). **Function** \[ f(x) = \boxed{} \] **Instructions for Solving** To find the polynomial \( f(x) \): 1. Note the given zeros \( 2i \) and \( 2 - i \). 2. Remember that complex roots occur in conjugate pairs in polynomials with real coefficients. Thus, the zeros are \( 2i, -2i, 2 - i, \) and \( 2 + i \). 3. Construct factors from these zeros: - \( (x - 2i) \) - \( (x + 2i) \) - \( (x - (2 - i)) \) - \( (x - (2 + i)) \) 4. Multiply the factors to form the polynomial using the identity \( (x-a)(x+a) = x^2-a^2 \) for complex conjugates. Using these steps, you will have the polynomial expression with the lowest degree and integer coefficients.
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