History Bookmarks Iools Help= fallacie XO Lumen OHMuntitled - T-Table.pdfBb Blackboard CollaboA https://ohm.lumenlearning.com/assess2/?cid3D483678&aid%3Dan Associatio..O QuickBooks G Google G Image result for narco..O http://r20.rs6.net• Question 2Test the claim that the mean GPA of night students is smaller than 2.8 at the 0.10 significance level.The null and alternative hypothesis would beHo:u = 2.8 He:p< 0.7 Ho:u < 2.8 He:p> 2.8 Ho:p 0.7 Ho:p> 0.7Hi:u 4 2.8 Hy:p > 0.7 Hi:> 28 H: 28 Hp/ 0.7 Hi:p< 0.7The test isright-tailed two-tailed left-taledBased on a sampie of 35 people. che sample mean GPA was 276 with a standard deviation of 0 08The test statistic isto 2 decmalsThe pivaluekro 2 decmaisBased on this weOReect the nu hypochesisOreoreact the nuil nypotressMozilla Fireto seems sio to start.Type here to search

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Description: History Bookmarks Iools Help= fallacie XO Lumen OHMuntitled - T-Table.pdfBb Blackboard CollaboA https://ohm.lumenlearning.com/assess2/?cid3D483678&aid%3Dan Associatio..O QuickBooks G Google G Image result for narco..O http://r20.rs6.net• Question 2T

From provided information, it is claimed that mean GPA of night students is smaller than 2.8 Hypotheses can be constructed as: H0: µ ≥ 2.8 H1: µ < 2.8 This is left tailed test. Based on sample of 35 people, sample mean GPA was 2.76 with standard deviation of 0.08 n=35 x̅=2.76 s=0.08Test statistic is: t=x-μs/n Test statistic follows t-distribution with n-1 degrees of freedom. t=2.76-2.80.08/35=-2.9580 Thus, test statistic is -2.96.The test is one tailed, follows t-distribution with 34 degrees of freedom. The p value of the test statistic from the t table is 0.00. The level of significance (α) = 0.1 Decision rule: Reject H0: if p value < level of significance (α) Since, the p value is 0.00 which is less than level of significance, therefore the null hypothesis would be rejected and it can be concluded that there is sufficient evidence to support the claim that mean GPA of night students is smaller than 2.8

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Test the claim that the mean GPA of night students is smaller than 2.8 at the 0.10 significance level. The null and alternative hypothesis would be Ho: 2.8 He:p<0.7 He:A< 28 He: 2.8 Ho:p 0.7 Hop 0.7 H:u 4 28 Hy:p>0.7 H:> 2.8 Ha 28 Hp/0.7 Hi:P< 0.7 The test is right-tailed two-tailed left-taled Based on a sample of 35 people the sample mean GPAWAS 276 with a standarddeviation of O.08 The test statiatic is (to 2 decmal The pivalue (to 2 decmal Based on this w hypoches ect the nuit nya

Test the claim that the mean GPA of night students is smaller than 2.8 at the 0.10 significance level. The null and alternative hypothesis would be Ho: 2.8 He:p<0.7 He:A< 28 He: 2.8 Ho:p 0.7 Hop 0.7 H:u 4 28 Hy:p>0.7 H:> 2.8 Ha 28 Hp/0.7 Hi:P< 0.7 The test is right-tailed two-tailed left-taled Based on a sample of 35 people the sample mean GPAWAS 276 with a standarddeviation of O.08 The test statiatic is (to 2 decmal The pivalue (to 2 decmal Based on this w hypoches ect the nuit nya

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.05 significance level. The null and alternative hypothesis would be: Ho p≥ 0.6 Ho: p=0.6 Hop=2.4 Ho: p ≤ 0.6 Ho: ≤2.4 Ho:μ ≥ 2.4 H₁: p0.6 H₁: μ> 2.4 H₁: μ< 2.4 The test is: left-tailed right-tailed O Based on a sample of 65 people, the sample mean GPA was 2.44 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) The p-value is: two-tailed O Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis (to 2 decimals)
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Read through this scenario and look at the data that was collected. State the null and all possible research hypotheses. Review the results below (I used SPSS) and answer the questions that follow. Scenario: A researcher wants to see if gender and / or income affects the total amount of help given to a stranger who is sitting on the side of a busy road with a sign asking for help. The independent variables are gender, income, and the interaction of gender and income. The dependent variable is total help. He wants to know if one or both factors – or the interaction of the two - affects the total amount of help offered. Because he is analyzing two independent variables (gender and income), he used a factorial ANOVA. His results show the main effect of each of the independent variables on the dependent variable (total help) and the interaction effect. The researcher is using a 95% confidence interval which means that he wants to be at least 95% sure that his independent variables…
Test the claim that the mean GPA of night students is smaller than 2.6 at the 0.01 significance level.The null and alternative hypotheses would be: H0:p=0.65H1:p<0.65 H0:p=0.65H1:p>0.65 H0:p=0.65H1:p≠0.65 H0:μ=2.6H1:μ≠2.6 H0:μ=2.6H1:μ<2.6 H0:μ=2.6H1:μ>2.6 Based on a sample of 33 people, the sample mean GPA was 2.59 with a standard deviation of 0.2The p-value is: (to 3 decimals)The significance level is: (to 2 decimals)
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The following hypotheses are given. H0: ρ ≤ 0 H1: ρ > 0 A random sample of 12 paired observations indicated a correlation of 0.32. State the decision rule for 0.05 significance level. (Round your answer to 3 decimal places.) Compute the value of the test statistic. (Round your answer to 2 decimal places.) Can we conclude that the correlation in the population is greater than zero? Use the 0.05 significance level.
The mean GPA of night students is significantly different than the mean GPA of day students at the 0.01 significance level. Null and alternative hypothesis? H0:μN=μD H1:μN≠μD When it says "significantly different" would we choose the option with the line going through the equal sign? The test is: two-tailed (Is this the choice for a hypothesis that has an equal sign with the line through it? left-tailed right-tailed Sample of 75-night students, a sample mean GPA of 3.47 and an SD of 0.03 Sample of 35-day students, a sample mean GPA of 3.45 and an SD of 0.04. The test statistic is: Do we use the z test or interval function on the calculator? The positive critical value is: How do we solve for critical value and then use this info to figure out if the hypothesis was rejected or failed? < Based on this we: Reject the null hypothesis OR Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .01 significance level. The null and alternative hypothesis would be: = PF Ho: M MF Ho: PM = PF Ho: M = μF Ho:μπ HF Ho: PM H₁:μM > μF H₁:PM
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