With source code file pls .To download it Write a C++ program to enter the values of a 4x3 array, then print the array andfind the largest, smallest, average value in each row as shown in the followingexample:1078.largest=10, smallest=7, Average=8.336.1largest=6, smallest=1, Average=38.61largest=8, smallest=1, Average=531largest=6, smallest=1, Average=3.332.

Answered: Write a C++ program to enter the values…

Computer Networking: A Top-Down Approach (7th Edition)

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ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

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With source code file pls . To download it

Write a C++ program to enter the values of a 4x3 array, then print the array and
find the largest, smallest, average value in each row as shown in the following
example:
10
7
8.
largest=10, smallest=7, Average=8.33
6.
1
largest=6, smallest=1, Average=3
8.
6
1
largest=8, smallest=1, Average=5
3
1
largest=6, smallest=1, Average=3.33
2.

Expert Solution

Code & Explanation

As per the rules we can't upload files. You have to copy it.

Here is the required code.

#include<iostream>

using namespace std;


int main() {
    // declare an array of 4x3 i.e. 4 rows and 3 columns
    int a[4][3];

    // take user input
    // outer for loop iterates for each row
    for (int i = 0; i < 4; i++) {
        // inner for loop iterates for each column in a row
        for (int j = 0; j < 3; j++) {
            // take the user input and store at ith row and jth column
            cin >> a[i][j];
        }
    }

    // insert a new line between input and output
    cout << endl;

    // now iterate over each row again
    // this time to calculate largest, smallest and average
    for (int i = 0; i < 4; i++) {

        // initialize largest with the smallest integer
        // choosing the smallest integer to compare with large values
        int largest = INT_MIN;

        // initialize smallest with the largest integer
        int smallest = INT_MAX;

        // initialize total to 0
        double total = 0;

        // iterate over each column in current row
        for (int j = 0; j < 3; j++) {
            // get the value at ith row and jth column
            int current_num = a[i][j];

            // add it to `total`
            total += current_num;

            // check if `current_num` is larger than `largest`
            if (current_num > largest) {
                // if yes, update largest
                largest = current_num;
            }

            // check if `current_num` is smaller than `smallest`
            if (current_num < smallest) {
                smallest = current_num;
            }

            // print the value with a tab
            cout << current_num << '\t';
        }

        // calculate average
        double avg = total / 3;

        // put 2 tabs
        cout << "\t\t";
        // print the largest value
        cout << "largest=" << largest;
        // print the smallest value
        cout << ", smallest=" << smallest;
        // print average
        cout << ", Average=" << avg;
        // insert a new line
        cout << endl;
    }

    return 0;
}