Write a C function that, given a square matrix of floats, finds the diagonal with maximum average value. The function should have the following prototype float matrMaxDiaq(float M[DIM] [DIM], int n); where DIM is the size of the matrix, and n (n <= DIM) Is the number of rows and columns that are actually used. The function calculates the average value of each diagonal, and then returns the maximum of such values. Example of execution: 1.0 2.0 3.0 4.0 5.0 1.0 2.0 3.0 4.0 5.0 2.0 2.0 2.0 2.0 -2.0 2.0 2.0 2.0 2.0 -2.0 50/1=5.0 1.1 2.2 3.3 -4.4 5.5 1.1 2.2 3.3 -4.4 5.5 2.0/2 = 1.0 2.2 2.2 -3.2 4.2 4.2 2.2 2.2 -3.2 4.2 4.2 10.5/3 = 3.5 1.8 -2.3 3.1 4.9 5.0 1.8 -2.3 3.1 4.9 5.0 3.8/4 0.95 15.5/5 = 3.1 -0.1/2= 6.4/3/= 59/4= 1.475 Max diag average: 5.0 0.05 2.133 寸寸 に -|2 269

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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This is not a graded question so please don't disregard it as if it is. Thank you in advance professor!
Write a C function that, given a square matrix of floats, finds the diagonal with maximum average value. The function should have
the following prototype:
float matrMaxDiaq(float M[DIM] [DIM], int n);
where DIMİis the size of the matrix, and n (n <= DIM) İs the number of rows and columns that are actually used.
The function calculates the average value of each diagonal, and then returns the maximum of such values,
Example of execution:
1.0
2.0
3.0
4.0
5.0
1.0
2.0
3.0
4.0
5.0
2.0
2.0
2.0
2.0
-2.0
2.0
2.0
2.0
2.0
-2.0
50/1 5.0
1.1
2.2
3.3
-4.4
5.5
1.1
2.2
3.3
-4.4
5.5
2.0/2 1.0
2.2
2.2
-3.2
4.2
4.2
2.2
2.2
-3.2
4.2
4.2
10.5/3 3.5
1.8
-2.3
3.1
4.9
5.0
1.8
-2.3
3.1
4.9
5.0
3.8/4 0.95
15.5/5 = 3.1
F18-012%= 6.4/3%3
59/4= 1.475
Max diag average: 5.0
0.05
2.133
45.
Transcribed Image Text:Write a C function that, given a square matrix of floats, finds the diagonal with maximum average value. The function should have the following prototype: float matrMaxDiaq(float M[DIM] [DIM], int n); where DIMİis the size of the matrix, and n (n <= DIM) İs the number of rows and columns that are actually used. The function calculates the average value of each diagonal, and then returns the maximum of such values, Example of execution: 1.0 2.0 3.0 4.0 5.0 1.0 2.0 3.0 4.0 5.0 2.0 2.0 2.0 2.0 -2.0 2.0 2.0 2.0 2.0 -2.0 50/1 5.0 1.1 2.2 3.3 -4.4 5.5 1.1 2.2 3.3 -4.4 5.5 2.0/2 1.0 2.2 2.2 -3.2 4.2 4.2 2.2 2.2 -3.2 4.2 4.2 10.5/3 3.5 1.8 -2.3 3.1 4.9 5.0 1.8 -2.3 3.1 4.9 5.0 3.8/4 0.95 15.5/5 = 3.1 F18-012%= 6.4/3%3 59/4= 1.475 Max diag average: 5.0 0.05 2.133 45.
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