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Write 54 as 2 x 27, 16 as 2 × 8, and simplify the expression. 3V16 – V50 = V2 - 27 + 3 2 - 8 – V50 = V2 - 33 + 3 V2 . 23 – V50 = 32 +3 · 2 2 – v50 = 3V2 + 6V2 - V50 %3D | Now add the similar radicals and simplify. V54 + 3V16 – V50 = 3 2 + 6v2 – V50 = (3 + 6) V2 – V50 = 9V2 - V50 7. 6553 | Answer: V54 + 3V16 – V50 z 7. 6553

Write 54 as 2 x 27, 16 as 2 × 8, and simplify the expression. 3V16 – V50 = V2 - 27 + 3 2 - 8 – V50 = V2 - 33 + 3 V2 . 23 – V50 = 32 +3 · 2 2 – v50 = 3V2 + 6V2 - V50 %3D | Now add the similar radicals and simplify. V54 + 3V16 – V50 = 3 2 + 6v2 – V50 = (3 + 6) V2 – V50 = 9V2 - V50 7. 6553 | Answer: V54 + 3V16 – V50 z 7. 6553

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Write 54 as 2 x 27, 16 as 2 × 8, and simplify the expression. 3V16 – V50 = V2 - 27 + 3 2 - 8 – V50 = V2 - 3 + 3 V2- 2 – V50 = 32 +3 · 2 2 – v50 = 32 + 6V2 - V50 %3D | Now add the similar radicals and simplify. V54 + 3V16 – V50 = 3 2 + 6V2 – V50 = (3 + 6) V2 – V50 = 9v2 - V50 7. 6553 | Answer: V54 + 316 – V 50 x 7. 6553
Transcribed Image Text:Write 54 as 2 x 27, 16 as 2 × 8, and simplify the expression. 3V16 – V50 = V2 - 27 + 3 2 - 8 – V50 = V2 - 3 + 3 V2- 2 – V50 = 32 +3 · 2 2 – v50 = 32 + 6V2 - V50 %3D | Now add the similar radicals and simplify. V54 + 3V16 – V50 = 3 2 + 6V2 – V50 = (3 + 6) V2 – V50 = 9v2 - V50 7. 6553 | Answer: V54 + 316 – V 50 x 7. 6553
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