Workers with a formal arrangement with their employer to be paid for time worked at home worked an average of 19 hours per week. A random sample of 15 mortgage brokers indicated that they worked a mean of 21.3 hours per week at home with a standard deviation of 6.5 hours. At α = 0.05, is there sufficient evidence to conclude a difference? Construct a 95% confidence interval for the true mean number of paid working hours at home. Compare the results of your confidence interval to the conclusion of your hypothesis test and discuss the implications.
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A: Given information- Sample size, n = 48 Sample mean, x-bar = 3.4 Sample standard deviation, s = 18.9…
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A: The changes in the levels of LDL cholesterol have a mean of and a standard deviation of 18.7. The…
Q: n a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: Given that Sample size =44 subjects Mean difference=3.4 Sample standard deviation (before-after)…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
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Q: and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL)…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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A: given data sample size (n) = 42sample mean ( xd¯ ) = 5.5sample standard deviation (sd) =17.490% ci…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
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A: From the provided information, Sample size (n) = 44 Sample mean (x̄) = 4.4 Sample standard deviation…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: Given : Sample Size, n = 42 Sample Mean, x̄ = 5.7 sample standard…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
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Workers with a formal arrangement with their employer to be paid for time worked at home worked an average of 19 hours per week. A random sample of 15 mortgage brokers indicated that they worked a mean of 21.3 hours per week at home with a standard deviation of 6.5 hours. At α = 0.05, is there sufficient evidence to conclude a difference? Construct a 95% confidence interval for the true mean number of paid working hours at home. Compare the results of your confidence interval to the conclusion of your hypothesis test and discuss the implications.
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- In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.8 and a standard deviation of 17.3. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. WWhat does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean p? mg/dLIn a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.7 and a standard deviation of 17.7. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean μ? ____mg/dL<μ<_____mg/dLIn a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 2.8 and a standard deviation of 16.3. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.5 and a standard deviation of 19.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? O mg/dL < µIn a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.5 and a standard deviation of 15.4. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.9 and a standard deviation of 15.3. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? | mg/dL < µIn a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.6 and a standard deviation of 17.5. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <µ< mg/dL (Round to two decimal places as needed.)In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.1 and a standard deviation of 16.5. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. LOADING...In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 2.0 and a standard deviation of 16.5. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?In a study of the use of hypnosis to relieve pain, sensory ratings were measured for 8 subjects and the mean sensory ratings was found to be 2.8 and standard deviation to be 0.3. The sensory ratings are normally distributed. The 80% confidence interval for the mean sensory ratings of the population is (9.35,11.65) b. (3.58, 4.64) (2.65, 2.95) d. (3.09, 3.91) (6.27, 8.73) a. C. e.In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.3 and a standard deviation of 17.4. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? . What is the confidence interval estimate of the population mean μ? enter your response here mg/dL<μ<enter your response here mg/dL (Round to two decimal places as needed.)In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (beforeafter) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.8 and a standard deviation of 19.2. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. 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