Work, Energy and Momentum Notes 4 Collisions in 2-D When dealing with collisions in 2-dimensions it is important to remember that momentum is a vector with magnitude and direction. When finding the total momentum we have to do: Collisions at 90°: We then add A 750 kg Peugeot travelling at 21 m/s West collides with a 680 kg Fiat travelling at 18 m/s South. If the two cars become entwined what is their total final velocity? Vz=18k F Pf=√√Pi²+ P₂² TMB=TMA P₁+ Pz = 1 = P V₁ = 21 m/s P P2 P₁ =(750)(21) •P2 = (680)(18) P₁ = 15750ky M15 Tan@= 12240 1570 P2=12240 kg/s == 0 = 38° Remember that it is momentum that is conserved, so we need to add the momentum V 19947 kgm/s = Pf m = 19947/1430 13.9 M/S VF = 14M/s at 38° Saf NOT velocity
Work, Energy and Momentum Notes 4 Collisions in 2-D When dealing with collisions in 2-dimensions it is important to remember that momentum is a vector with magnitude and direction. When finding the total momentum we have to do: Collisions at 90°: We then add A 750 kg Peugeot travelling at 21 m/s West collides with a 680 kg Fiat travelling at 18 m/s South. If the two cars become entwined what is their total final velocity? Vz=18k F Pf=√√Pi²+ P₂² TMB=TMA P₁+ Pz = 1 = P V₁ = 21 m/s P P2 P₁ =(750)(21) •P2 = (680)(18) P₁ = 15750ky M15 Tan@= 12240 1570 P2=12240 kg/s == 0 = 38° Remember that it is momentum that is conserved, so we need to add the momentum V 19947 kgm/s = Pf m = 19947/1430 13.9 M/S VF = 14M/s at 38° Saf NOT velocity
College Physics
11th Edition
ISBN:9781305952300
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Help :,) I can’t seem to figure out what’s going on here, an explanation to this problem would help a lot , thank you!!
![Work, Energy and Momentum Notes
4 Collisions in 2-D
When dealing with collisions in 2-dimensions it is important to remember that momentum is a vector with
magnitude and direction. When finding the total momentum we have to do:
Collisions at 90°:
We then add
A 750 kg Peugeot travelling at 21 m/s West collides with a 680 kg Fiat travelling at 18 m/s South. If the two cars
become entwined what is their total final velocity?
Vz=18k F
Pf=√√Pi²+ P₂²
TMB=TMA
P₁+ Pz = 1
=
P
V₁ = 21 m/s
P
P2
P₁ =(750)(21)
•P2 = (680)(18)
P₁ = 15750ky M15
Tan@=
12240
1570
P2=12240 kg/s
== 0 = 38°
Remember that it is momentum that is conserved, so we need to add the momentum
V
19947 kgm/s
=
Pf
m
= 19947/1430
13.9 M/S
VF = 14M/s at 38°
Saf
NOT velocity](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd08a6c19-dc79-4368-8e35-820b976eb472%2F2573ede8-64e9-4d18-9473-d0520598a782%2Fshfyymr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Work, Energy and Momentum Notes
4 Collisions in 2-D
When dealing with collisions in 2-dimensions it is important to remember that momentum is a vector with
magnitude and direction. When finding the total momentum we have to do:
Collisions at 90°:
We then add
A 750 kg Peugeot travelling at 21 m/s West collides with a 680 kg Fiat travelling at 18 m/s South. If the two cars
become entwined what is their total final velocity?
Vz=18k F
Pf=√√Pi²+ P₂²
TMB=TMA
P₁+ Pz = 1
=
P
V₁ = 21 m/s
P
P2
P₁ =(750)(21)
•P2 = (680)(18)
P₁ = 15750ky M15
Tan@=
12240
1570
P2=12240 kg/s
== 0 = 38°
Remember that it is momentum that is conserved, so we need to add the momentum
V
19947 kgm/s
=
Pf
m
= 19947/1430
13.9 M/S
VF = 14M/s at 38°
Saf
NOT velocity
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