wo bulbs, each of a type with average lifetime 1,500 hours. Assuming that we can model the probability of failure of a bulb by an exponential density function with mean 1,500, find the probability that both of the lamp's bulbs fail within 1,600 hours. ( es.) J has just one bulb of the same type as in part (a). If one bulb burns out and is replaced by a bulb of the same type, find the probability that the two bulbs fail within a total of 1,600 hours. (Round your answer to four decimal places.) J

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Q: 2= 2.500 12=2.33 12 2.807 /2 2.575

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Q: what is 3.07( 0.969)t  as a percentage rate

A: The solution is given below

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A:

Q: .8335 2ndrarmalede (-10,0001.96 0. c. 0.0128

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Q: 0.02)(75,704)(950,715)/20

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Q: Round

A: 0.766891 ~ 0.76689, in the nearest hundred thousand

Q: t says the answer is 0.8597 I'm not sure how they got that

A: The mean is 97.7 and the standard deviation is 0.6.

Q: How do you round -9.9992 to two decimal points?

A: -9.9992