Without further clarifying, a news report provided a binomial confidence interval to describe the probability of an event as between 0.591 and 0.749 based on an experiment with 25 trials. a. What was the margin of error in their interval? b. What was the success rate within the sample? c. What confidence level did they use?

Q: In a random sample of 100 men in the United States, 55 of them were married. Using a 95% confidence…

A: We have given that,  Sample size (n) = 100 and favorable cases (X) = 55  Then,  We will find the 95…

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: a certain presidential election, Alaska's 40 election districts averaged 1,953.8 votes per district…

A: given data, bell- shaped distribution μ=1593.8σ=572.2x= number of votes for this candidate for an…

Q: A national air traffic control system handled an average of 47,189 flights during 29 randomly…

A: The sample size is 29The sample mean is 47189The sample standard deviation is 6351We have to…

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A: We have given that,  Sample mean (x̄) = 34, standard deviation (s)=6 and sample size (n) = 10 Then,…

Q: Find the margin of error at a 90% confidence level.

A:

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: A poll for a statewide election has a margin of error of 2.14 percentage points. How many voters…

A: From the provided information,Margin of error (E) = 0.0214Confidence level = 99%

Q: In a random sample of 75 college students 60 of them had sunglasses.  Compute a 95% Confidence…

A: Thank you for posting the question. Since you have asked multiple question, we will solve the first…

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: According to a survey, 66% of all students in the U. S. own a laptop. For a simple random sample of…

A: It is given that, According to a survey, 66% of all students in the U. S. own a laptop i.e. the…

Q: In a survey, 15 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 32 people were asked how much they spent on their child's last birthday gift. The…

A: Given  sample size n=32 mean x¯=$33 standard deviation s=$12 confidence level =80%,…

Q: We are interested in comparing the percentage of females versus males who expect their future to be…

A: Summarising the given information below. The number of total surveyed females and males:…

Q: On September 14, 2000, a cross-sectional survey of 24,000 residents of a western state revealed that…

A: Given: n = 24000 Number of tuberculosis cases X = 145 Proportion p^ = Xn Formula Used: Confidence…

Q: 1. A poll of 2,500 people shows that 50% approve of a smoking ban in bars and restaurants. What is…

A:

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Using excel formula “=T.INV(1-(0.2/2),22)”, the critical value of 80% confidence level is 1.321.

Q: Suppose we observed 15 successes in a random sample of 60 subjects. What is the 99% confidence…

A:

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A: It is given that  Sample mean = 46 Sample standard deviation = 10 Sample size = 28

Q: The US Treasury found that a random sample of 1309 $20 bills found that 837 of them had trace…

A:

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Sample mean = x̅ = 46 Sample size = n = 23 Sample S.D = s = 12 Standard Error = s/√n  = 12/√23…

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

A:

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: See the handwritten solution

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: Given information- Sample size, n = 14 Mean, x-bar = $32 Standard deviation, s = $20 Confidence…

Q: Which estimate at a 95% confidence level most likely comes from a small sample? OA. 78% (14%) OB.…

A: The provided information is  α=0.05 The critical value is  z=1.96    (from statistical table)…

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: We take a sample of 218 men and find they have an average commute time of 32 minutes with a standard…

A: Given: a sample of 218 men and find they have an average commute time of 32 minutes with a standard…

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=23sample mean (x) = 31standard deviation (s) = 8α = 1-0.95=0.05α2=0.025degrees…

Q: In a survey, 32 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 13 people were asked how much they spent on their child's last birthday gift. The…

A: From the provided information, Sample size (n) = 13 Sample mean (x̄) = 50 Sample standard deviation…

Q: The Highway Safety Department wants to study the driving habits of individuals. A sample of 81 cars…

A: Given information Sample size (n) = 81 Sample mean x̅ = 67 mph Standard deviation (s) = 9 mph…

Q: In a survey, 22 people were asked how much they spent on their child's last birthday gift. The…

A: It is given that n=22, x=34 and s=5. At 98% confidence level, the value of z is 2.326.