With the choice of thumbnails labeled A to K below, construct a comic strip depicting the complete mechanism of benzene nitration. List all the steps and in the correct order. Enter your answer as follows: ABCDEF (sequence of capital letters without spaces). N.B. There are more thumbnails than necessary.
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![A
D
O=NⒸ |-0--0-H
F
J
H
O=N=O
H
CI
e
O-S-O-H
O=N=O
CI
CIRI-CI
O=NⒸ
BO
O=NⒸ
+ H₂O
H₂SO4
CI
+ HCI + AICI 3
OZNEO
E
K
+ H₂SO4
Hi
CI
CI-CI AI-CI
O-NH-O-S-O-H
ofo
-O-H
D-H
08.08
O=N
H
đa
O=N
O
H H
O=NEO
CI
CI+CI-I-CI
NO₂
+
O=N=O + H₂O
HSO4
H₂SO4
NO₂
H₂SO4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F29f5d7eb-4249-400c-9812-e7a08e4caa6a%2Fa098dbe8-a620-46bd-ad0a-e4d7028a503b%2Fwjgzbms_processed.jpeg&w=3840&q=75)
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