Question 16With reference to the diagram above, select the correct expression for the workdone by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force ofkinetic friction is fuk * N in the direction opposite of motion. Hint #2:While on the incline, the magnitude of the normal force on the sled isN = m* g* cos (15º).W; = 0OW;Hk * m * g * h * cos (180°)'W;Hk * m * g * cos (15°) *hsin(15°)cos (180°)OW; = µk * m * g * h * cos (15°)OW;cos (15°) * h * sin (15°) * cos (180°)m The Super Sled travels with an initial kinetic energy of 3369 J horizontally and to theright along a frictionless flat surface, initially at a height of zero (initial gravitationalpotential energy = 0). The driver briefly engages the rocket over a distance (Ax) of2.000 m, pushing the sled with a force of 400.0 N over that distance. The rocket isthen turned off. The sled then goes up an inclined surface with a rough surface. Thecoefficient of kinetic friction on the incline is uk. At the top of the incline, the sledreaches a height h = 1.500 m above the ground where the surface becomes flat andfrictionless again. The sled (including the rocket and driver) has a total mass of 87.00kg.(Notes: assume that g = 9.810 m/s² , and that the mass of fuel used by the rocket isnegligible. Do not use scientific notation).After &,rocketrocketBefore propulsionpropulsionstartsendsrough inclined surfacerocketfrictionlessengagedcoefficient of kinetic friction = Hsurfaceh = 1.500 m15.000)frictionlesssurfaceAx = 2.000 m

Name: Question 16With reference to the diagram above, select the correct ex
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Description: Question 16With reference to the diagram above, select the correct expression for the workdone by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force ofkinetic friction is fuk * N in the direction opposite of motion. Hint #2:Whi

W = F.S Cosθ Here, F =Force = Friction = UN = Uk *Mg cos 15° S = net displacement parallel or…

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With reference to the diagram above, select the correct expression for the work done by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force of kinetic friction is f While on the incline, the magnitude of the normal force on the sled is N = m*g* = uk * N in the direction opposite of motion. Hint #2: cos (15°).

With reference to the diagram above, select the correct expression for the work done by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force of kinetic friction is f While on the incline, the magnitude of the normal force on the sled is N = mg = uk * N in the direction opposite of motion. Hint #2: cos (15°).

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The Super Sled travels with an initial kinetic energy of 3369 J horizontally and to the right along a frictionless flat surface, initially at a height of zero (initial gravitational potential energy = 0). The driver briefly engages the rocket over a distance (Ax) of 2.000 m, pushing the sled with a force of 400.0 N over that distance. The rocket is then turned off. The sled then goes up an inclined surface with a rough surface. The coefficient of kinetic friction on the incline is uk. At the top of the incline, the sled reaches a height h = 1.500 m above the ground where the surface becomes flat and frictionless again. The sled (including the rocket and driver) has a total mass of 87.00 kg. (Notes: assume that g = 9.810 m/s² , and that the mass of fuel used by the rocket is negligible. Do not use scientific notation). After &, rocket rocket Before propulsion propulsion starts ends rough inclined surface rocket frictionless engaged coefficient of kinetic friction = H surface h = 1.500 m…
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