Question 16With reference to the diagram above, select the correct expression for the workdone by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force ofkinetic friction is fuk * N in the direction opposite of motion. Hint #2:While on the incline, the magnitude of the normal force on the sled isN = m* g* cos (15º).W; = 0OW;Hk * m * g * h * cos (180°)'W;Hk * m * g * cos (15°) *hsin(15°)cos (180°)OW; = µk * m * g * h * cos (15°)OW;cos (15°) * h * sin (15°) * cos (180°)m The Super Sled travels with an initial kinetic energy of 3369 J horizontally and to theright along a frictionless flat surface, initially at a height of zero (initial gravitationalpotential energy = 0). The driver briefly engages the rocket over a distance (Ax) of2.000 m, pushing the sled with a force of 400.0 N over that distance. The rocket isthen turned off. The sled then goes up an inclined surface with a rough surface. Thecoefficient of kinetic friction on the incline is uk. At the top of the incline, the sledreaches a height h = 1.500 m above the ground where the surface becomes flat andfrictionless again. The sled (including the rocket and driver) has a total mass of 87.00kg.(Notes: assume that g = 9.810 m/s² , and that the mass of fuel used by the rocket isnegligible. Do not use scientific notation).After &,rocketrocketBefore propulsionpropulsionstartsendsrough inclined surfacerocketfrictionlessengagedcoefficient of kinetic friction = Hsurfaceh = 1.500 m15.000)frictionlesssurfaceAx = 2.000 m

Name: Question 16With reference to the diagram above, select the correct ex
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: Question 16With reference to the diagram above, select the correct expression for the workdone by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force ofkinetic friction is fuk * N in the direction opposite of motion. Hint #2:Whi

W = F.S Cosθ Here, F =Force = Friction = UN = Uk *Mg cos 15° S = net displacement parallel or…

Science

Physics

With reference to the diagram above, select the correct expression for the work done by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force of kinetic friction is f While on the incline, the magnitude of the normal force on the sled is N = m*g* = uk * N in the direction opposite of motion. Hint #2: cos (15°).

With reference to the diagram above, select the correct expression for the work done by friction (W f) on the sled. DO NOT GUESS, work it out! Hint 1: the force of kinetic friction is f While on the incline, the magnitude of the normal force on the sled is N = mg = uk * N in the direction opposite of motion. Hint #2: cos (15°).

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Which of the following is the correct way to calculate work? F is the magnitude of the Force and d is the magnitude of the Displacement. Answers: W = Fdcosα, α is the angle between the Force vector and Displacement vector W = Fd W = Fdsinα, α is the angle between the Force vector and Displacement vector W = F/d
I need help with #1a and 1b please
Find the work done in the figure below. The magnitude of F= 36 N. The displacement is d= -4.0 m/ and 0 = 120°. y d Enter to 2 significant figures W = 72 F -X X Making sense: Do you predict positive, negative or zero work? Does your answer support the prediction?
A crate with mass m = 33.3 kg being pushed up an incline that makes an angle φ = 22.7 degrees with horizontal. The pushing force is horizontal, with magnitude P, and the coefficient of kinetic friction between the crate and the incline is μ = 0.358. Consider the work done on the crate as it moves a distance d = 5.32 m at constant speed. a. What is work done by the pushing force, in joules? b. What is the work done by friction, in joules? c. What is the work done by gravity, in joules? d. What is the net work, in joules?
Please answer question and just send me the paper solutions asap dont type the answer please question 5 please give me the right solutions and answers please and label the given and draw a diagram and show the work please help me faster asap and don't give wrong answer
Part A What is the minimum work needed to push a 900-kg car 860 m up along a 9.5° incline? Ignore friction. Express your answer with the appropriate units. WP = µÅ Value Units ?
The Super Sled travels with an initial kinetic energy of 3369 J horizontally and to the right along a frictionless flat surface, initially at a height of zero (initial gravitational potential energy = 0). The driver briefly engages the rocket over a distance (Ax) of 2.000 m, pushing the sled with a force of 400.0 N over that distance. The rocket is then turned off. The sled then goes up an inclined surface with a rough surface. The coefficient of kinetic friction on the incline is uk. At the top of the incline, the sled reaches a height h = 1.500 m above the ground where the surface becomes flat and frictionless again. The sled (including the rocket and driver) has a total mass of 87.00 kg. (Notes: assume that g = 9.810 m/s² , and that the mass of fuel used by the rocket is negligible. Do not use scientific notation). After &, rocket rocket Before propulsion propulsion starts ends rough inclined surface rocket frictionless engaged coefficient of kinetic friction = H surface h = 1.500 m…
What are the solutions for this problem? The answers are already given.
Please only answer D and E with work shown please, thank you.
Please answer all parts and include explanations for each part that are easy to follow/understand.
Question 1 The first question does not require the coefficient of friction. Doesn't all the work being performed by the system = friction? Friction is the only thing that is performing work?
Please asap