With no magnetic field, the spectral line representing the transition from the 2P1/2 state to the 2S1/2 state in sodium has the wavelength 589.76 nm (see Figure 8.16). This is one of the two strong yellow lines in sodium. Calculate the difference in wavelength between the shortest and longest wavelength between these two states when placed in a magnetic field of 2.50 T. Energy2Ps/22pFigure 8.16 Schematic diagramof anomalous Zeeman effect forsodium (energy levels not toscale). With Be = 0 for the un-perturbed states, there is only onetransition. With the spin-orbit in-teraction splitting the 2P stateinto two states, there are two pos-sible transitions when B = 0. Fi-nally, B splits Jinto 2/ + 1 com-ponents, each with a different my.The energy splitting AE for eachmajor state is different becauseAE = gmy (eh2m)Best and theLandé g factor for glAE(S/2)] >g[AE¢P2)] > g[AE(-P,/2)]. AllUnperturbedWithWithspin-orbitinteractionstatesPextBest= 0allowed transitions are shown.-IN+ + IL

Answered: Image /qna-images/answer/bc780259-3fee-43f9-8369-f85532f8bb63.jpg

With no magnetic field, the spectral line representing the transition from the 2P1/2 state to the 2S1/2 state in sodium has the wavelength 589.76 nm (see Figure 8.16). This is one of the two strong yellow lines in sodium. Calculate the difference in wavelength between the shortest and longest wavelength between these two states when placed in a magnetic field of 2.50 T.

With no magnetic field, the spectral line representing the transition from the 2P1/2 state to the 2S1/2 state in sodium has the wavelength 589.76 nm (see Figure 8.16). This is one of the two strong yellow lines in sodium. Calculate the difference in wavelength between the shortest and longest wavelength between these two states when placed in a magnetic field of 2.50 T.

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