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A hydrogen atom emits light and ends in a state characterized by n₂ = 2. If the wavelength of the light emitted is 434
nm, use the Rydberg formula below to find the value of n₁ that characterizes the initial state of the atom. (RH=
1.09737316 × 107 m-1)
(3)
H
2
2
n
n
2
1
-=R
2

Expert Solution

Step 1

we have n₂ = 2

$λ$ =434nm = 434 $\times$ 10^-9m

R_H = 1.09737316 $\times$ 10⁷ m^-1

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