wire is composed of aluminum with length 1 = 0.450m and mass per unit length ₁ = 1.57g/m joined to a steel section with length 2 = 0.812m and mass per unit length 142 0.748g/m. This composite wire is fixed at both ends and held at a uniform tension of 141 N. ▼ Part A Find the lowest frequency standing wave that can exist on this wire, assuming there is a node at the joint between aluminum and steel. Submit ▾ Part B [ΨΕΙ ΑΣΦ n= 1 Request Answer Submit → IVE ΑΣΦ 3 → How many nodes (including the two at the ends) does this standing wave possess? Request Answer w ? DMC Hz ? nodes.

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Chapter1: Units, Trigonometry. And Vectors
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A wire is composed of aluminum with length 1 = 0.450m
and mass per unit length μ1 = 1.57g/m joined to a steel
section with length 2 = 0.812m and mass per unit length
0.748g/m. This composite wire is fixed at both ends
and held at a uniform tension of 141 N .
μ2
=
Part A
Find the lowest frequency standing wave that can exist on this wire, assuming there is a node at the joint between aluminum and steel.
f =
Submit
Part B
n =
{ΠΙ ΑΣΦ
Submit
Request Answer
How many nodes (including the two at the ends) does this standing wave possess?
V—| ΑΣΦ
Request Answer
?
www
Hz
?
nodes
Transcribed Image Text:A wire is composed of aluminum with length 1 = 0.450m and mass per unit length μ1 = 1.57g/m joined to a steel section with length 2 = 0.812m and mass per unit length 0.748g/m. This composite wire is fixed at both ends and held at a uniform tension of 141 N . μ2 = Part A Find the lowest frequency standing wave that can exist on this wire, assuming there is a node at the joint between aluminum and steel. f = Submit Part B n = {ΠΙ ΑΣΦ Submit Request Answer How many nodes (including the two at the ends) does this standing wave possess? V—| ΑΣΦ Request Answer ? www Hz ? nodes
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