w?Ip101 = k¢1(01 – 02) eq.4 .... w?Ip202 = kt1 (02 – 0,) +kr2 (02 – 03) eq.5 - .... .. ... w?Ip303 = kr2 (03 – 02) . .eq.6 Summing these equations gives: = 0........ eq.7 ... Derive Equations 9 and Equation 10 step by step Note: I think there is an error in Equation 10, please make sure 01 1 eq.8 Assume 01=1 ... w? Ip1 02 = 01 eq.9 - kti w?(Ip1+lpz) 03 = 02 eq.10 .... kt1

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w?Ip181 = ke1 (01 – 02)
eq.4
|
w?Ip202 = kea (02 – 0,) +k2 (02 – O3)
eq.5
-
w?Ip303 = kr2(03 – 02) ...
...eq.6
-
Summing these equations gives:
E=1 w?Ipi0; = 0....
.. eq.7
Derive Equations 9 and Equation 10 step by step
Note: I think there is an error in Equation 10, please make sure
= 1
eq.8 Assume 01=1
w? Ip1
02 = 01 –
· eq.9
%3D
kt1
w?(Ipı+/p2)
03 = 02 -
eq.10
kt1
Transcribed Image Text:w?Ip181 = ke1 (01 – 02) eq.4 | w?Ip202 = kea (02 – 0,) +k2 (02 – O3) eq.5 - w?Ip303 = kr2(03 – 02) ... ...eq.6 - Summing these equations gives: E=1 w?Ipi0; = 0.... .. eq.7 Derive Equations 9 and Equation 10 step by step Note: I think there is an error in Equation 10, please make sure = 1 eq.8 Assume 01=1 w? Ip1 02 = 01 – · eq.9 %3D kt1 w?(Ipı+/p2) 03 = 02 - eq.10 kt1
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