Why VB is equals to (-20i)in./s? Can someone explain
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Why VB is equals to (-20i)in./s?
Can someone explain
![76.2
2:47 PM
"O.
A 29
K/s
USM-CEN
2-BSABE-B
Calculate the velocity of coll ar B.
VB = Oxr3
V3 = (4k)×(5j)
V3 =(-20i)in./s
LIT 111A:
Literature
I hilipp
Calculate the accelerati on of collar B.
a; = [4k×(-20i)]+[(3k)×(5j)]
%3D
a3 =(-15i – 80j)in./s?
Calculate the velocity of collar C relative to the collar B.
C/B
VCB =(-3k)+(2i)x(4i – 4k)
VCE = (8j- 3k)in./s
Calculate the accelerati on of collar Crelative to the collar B.
j-Sk +[(2i)×(-3k)]+[(8i)×(4i-4k)]
+[(21)×(8j- 3k)]
acB
acs-
j-8k +[(6i)]+[(32i)]+[(16k +6j]}
aCB =(-2.25i +44j + 8k)in./s?
Calculate the velocity of collar C.
Vc =V3+0xrcB+ VC/B
Vc =(-20i)+(4k)x(4i – 4k)+(8j– 3k)
Vc =(-20i)+(16j)+(8j – 3k)
Vc =(-20i +24j- 3k )in./s
Calculate the accel eration of collar C.
ac = a3 +(óxrc3)+ox(@xrc3)+(2oxv3)+acB
[(-15i – 80j) +[(3k)×(4i – 4k)]+(4k)x(4kx(4i- 4k)
ac
(+(2(4k)x(8i – 3k))+(-2.25i + 44j+8k)
|
(-15i -80j) + [(12)]+(4k)×(16j)]
ac
(+(64j) +(-2.25i+ 44j+8k)
ac = {(-15i – 80j)+[(12j)]+(-64i)+(64j)+(-2.25i + 44j + 8k
%3D
ac =(-145i- 24j+ 8k)in./s²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F968374dc-5a0b-47ae-8564-d1a542c61509%2Fb39e7ad4-f0fc-433e-9bb3-df9c371ef7de%2Fgelme8j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:76.2
2:47 PM
"O.
A 29
K/s
USM-CEN
2-BSABE-B
Calculate the velocity of coll ar B.
VB = Oxr3
V3 = (4k)×(5j)
V3 =(-20i)in./s
LIT 111A:
Literature
I hilipp
Calculate the accelerati on of collar B.
a; = [4k×(-20i)]+[(3k)×(5j)]
%3D
a3 =(-15i – 80j)in./s?
Calculate the velocity of collar C relative to the collar B.
C/B
VCB =(-3k)+(2i)x(4i – 4k)
VCE = (8j- 3k)in./s
Calculate the accelerati on of collar Crelative to the collar B.
j-Sk +[(2i)×(-3k)]+[(8i)×(4i-4k)]
+[(21)×(8j- 3k)]
acB
acs-
j-8k +[(6i)]+[(32i)]+[(16k +6j]}
aCB =(-2.25i +44j + 8k)in./s?
Calculate the velocity of collar C.
Vc =V3+0xrcB+ VC/B
Vc =(-20i)+(4k)x(4i – 4k)+(8j– 3k)
Vc =(-20i)+(16j)+(8j – 3k)
Vc =(-20i +24j- 3k )in./s
Calculate the accel eration of collar C.
ac = a3 +(óxrc3)+ox(@xrc3)+(2oxv3)+acB
[(-15i – 80j) +[(3k)×(4i – 4k)]+(4k)x(4kx(4i- 4k)
ac
(+(2(4k)x(8i – 3k))+(-2.25i + 44j+8k)
|
(-15i -80j) + [(12)]+(4k)×(16j)]
ac
(+(64j) +(-2.25i+ 44j+8k)
ac = {(-15i – 80j)+[(12j)]+(-64i)+(64j)+(-2.25i + 44j + 8k
%3D
ac =(-145i- 24j+ 8k)in./s²
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