Why the passage of time is different for the observers on Earth and outside the Earth?
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Why the passage of time is different for the observers on Earth and outside the Earth?
Here time dilation is the phenomenon in which the time passes slower for an observer who is moving relative to another observer.
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- 11. A star is 40.0 light-years from Earth (1 light-year is the distance that light travels in 1 year). (a) How far would you measure this distance to be if you traveled it in a spaceship moving at 1.00 x 108 m/s? (b) How long would the trip last (for you)?The speed of light in space is 3.00 x 108 m/s. The time for light from the Sun to reach Earth is 8 minutes 20 seconds. Therefore, the distance from the Sun to Earth is 2.40 x 109 m. 8.64 x 1012 m. 1.50 x 1011 m. 2.25 x 109 m.What are the two postulates of Einstein's special theory of relativity?
- A square with an edge 8 cm long has an area of (8cm)(8cm) = 64 cm2. What is this area in square meters? Group of answer choices 0.64 square meters 0.0064 square meters 6400 square meters 640,000 square meters Which of the following does NOT correspond to the dimension of length? Group of answer choices fathom yard kilometer parsec angstrom light-year More than one of these is not a unit of length All of these are units of lengthA probe in outer space starts at rest. It accelerates at 23 m/s2 for 11 s, and then after that it coasts for the same amount of time. Calculate the total distance traveled by the probe, in m. (Please answer to the fourth decimal place - i.e 14.3225)7
- When a falling meteoroid is at a distance above the Earth's surface of 2.4 times the Earth's radius, what is its acceleration due to the Earth's gravitation? (Units: m/s2)A spaceship is moving in an elliptical motion. Their position (x, y) is described by the equation (x^2)/4 + (y-5)^2 = 9 Here, x represents their horizontal position (in km) and y represents the height (in km) of the spaceship: (a) An observer at a certain instant sees the shadow of the spaceship at x = 2 km and observes that the shadow is moving with a speed of 100 km per hour in the positive x direction. The observer also notes that the spaceship is ascending at this instant. How fast is the vertical motion of the spaceship at this instant? Give an exact answer. (b) Assuming that the spaceship doesn’t alter its course, is it moving in a clockewise or counterclockwise motion? (c) The speed of the spaceship is defined by the quantity Square root ((dx/dt)^2 + (dy/dt)^2). What is the speed of the spaceship in Part (a)? You may approximateTwo twins leave Earth at the same time in two different space ships. Jeremy travels twice as fast as Marnie. What will happen to them after they travel for one year of time back on Earth?
- I'm having trouble completing the problem I've attached a picture of below. I was able to find the the Earth's average speed in m/s relative to the sun by doing (2pi*(1.49x10^11))/31536000. But I am struggling to find the average velocity for the same thing over a period of one year in m/s. I was wondering how to calculate that? I've tried doing the (final velocity-initial velocity)/2 but the program doesn't accept my answer when using that approach.What are the two postulates of the special theory of relativity?Suppose astronomers found evidence of an earth-like planet 20 lightyears away. a) what may be two ethical considerations that one may consider when deciding if humans should travel to this planet? b) how fast would a spaceship need to travel if the roundtrip can no take longer than 40 years for the astronauts? c) how much time will the trip take according to the people on earth?