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7. At 25 °C, 0.0010 M NH4OH has a conductivity of 3.40 x 10-³ Sm¹¹. Given (in Sm²mol-¹): A, (NH4CI) = 0.0147, A. (NaOH) = 0.02481, A, (NaCl) = 0.01265, Calculate K.

7. At 25 °C, 0.0010 M NH4OH has a conductivity of 3.40 x 10-³ Sm¹¹. Given (in Sm²mol-¹): A, (NH4CI) = 0.0147, A. (NaOH) = 0.02481, A, (NaCl) = 0.01265, Calculate K.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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7. At 25 °C, 0.0010 M NH4OH has a conductivity of 3.40 x 10-³ Sm¹¹. Given (in Sm²mol-¹): A, (NH4C1) = 0.0147, A. (NaOH) = 0.02481, A, (NaCl) = 0.01265, Calculate Kb.
Transcribed Image Text:7. At 25 °C, 0.0010 M NH4OH has a conductivity of 3.40 x 10-³ Sm¹¹. Given (in Sm²mol-¹): A, (NH4C1) = 0.0147, A. (NaOH) = 0.02481, A, (NaCl) = 0.01265, Calculate Kb.
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Why the concnetration with mol/dm^3 was used in kb calculations with no conversion to mol/m^3 to have a coherent units?

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Thank you, but why you used the 0.0010 M (mol/dm^3) when calculating the Kb without converting it to mol/m^3 so we can have a coherent units?

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