Why should the **head in insert_atFront function has two asterisk (*)?

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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  1. Why should the **head in insert_atFront function has two asterisk (*)?
  2. Why should the searchNode return a pointer?
PRACTICE 6
Test the following additional functions in your program:
void insert_atFront(node **head, int n)
void insert_atPosition(node **head, int pos, int v)
node *searchNode(node *head, int n)
bool deleteNode(node **head, int n)
TIPS: deleteNode function need to call searchNode first to get whether the node exist
in the list. If the returned node is not NULL, then delete the node.
Transcribed Image Text:PRACTICE 6 Test the following additional functions in your program: void insert_atFront(node **head, int n) void insert_atPosition(node **head, int pos, int v) node *searchNode(node *head, int n) bool deleteNode(node **head, int n) TIPS: deleteNode function need to call searchNode first to get whether the node exist in the list. If the returned node is not NULL, then delete the node.
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#include <iostream>
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using namespace std;
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//struct
5 - struct node {
int x;
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node *next;
};
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//initialize head
11 E void initNode (node *head, int n) {
head->x = n;
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head->next = NULL;
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}
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//add a node to the list at tail
17 E void addNode (node *head, int n) {
node *newNode = new node;
newNode ->x = n;
newNode ->next = NULL;
node *cur = head;
while(cur) {
if(cur->next == NULL) {
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cur->next = newNode;
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return;
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cur = cur->next;
}
}
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Transcribed Image Text:1 #include <iostream> 2 using namespace std; 3 4 //struct 5 - struct node { int x; 7 node *next; }; 10 //initialize head 11 E void initNode (node *head, int n) { head->x = n; 12 13 head->next = NULL; 14 } 15 //add a node to the list at tail 17 E void addNode (node *head, int n) { node *newNode = new node; newNode ->x = n; newNode ->next = NULL; node *cur = head; while(cur) { if(cur->next == NULL) { 16 18 19 20 21 22 23 24 cur->next = newNode; 25 return; 26 cur = cur->next; } } 27 28 29
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