ANSWER THIS QUESTIONWhy should the **head in insert_atFront function has two asterisk (*)?Why should the searchNode return a pointer? PRACTICE 6Test the following additional functions in your program:void insert_atFront(node **head, int n)void insert_atPosition(node **head, int pos, int v)node *searchNode(node *head, int n)bool deleteNode(node **head, int n)TIPS: deleteNode function need to call searchNode first to get whether the node existin the list. If the returned node is not NULL, then delete the node. 1#include 2using namespace std;34//struct5 - struct node {int x;7node *next;};10//initialize head11 E void initNode (node *head, int n) {head->x = n;1213head->next = NULL;14}15//add a node to the list at tail17 E void addNode (node *head, int n) {node *newNode = new node;newNode ->x = n;newNode ->next = NULL;node *cur = head;while(cur) {if(cur->next == NULL) {1618192021222324cur->next = newNode;25return;26cur = cur->next;}}272829

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Why should the **head in insert_atFront function has two asterisk (*)?

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter17: Linked Lists

Section: Chapter Questions

Problem 13PE

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ANSWER THIS QUESTION

Why should the **head in insert_atFront function has two asterisk (*)?
Why should the searchNode return a pointer?

PRACTICE 6
Test the following additional functions in your program:
void insert_atFront(node **head, int n)
void insert_atPosition(node **head, int pos, int v)
node *searchNode(node *head, int n)
bool deleteNode(node **head, int n)
TIPS: deleteNode function need to call searchNode first to get whether the node exist
in the list. If the returned node is not NULL, then delete the node.

1
#include <iostream>
2
using namespace std;
3
4
//struct
5 - struct node {
int x;
7
node *next;
};
10
//initialize head
11 E void initNode (node *head, int n) {
head->x = n;
12
13
head->next = NULL;
14
}
15
//add a node to the list at tail
17 E void addNode (node *head, int n) {
node *newNode = new node;
newNode ->x = n;
newNode ->next = NULL;
node *cur = head;
while(cur) {
if(cur->next == NULL) {
16
18
19
20
21
22
23
24
cur->next = newNode;
25
return;
26
cur = cur->next;
}
}
27
28
29

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