Why is the pH of the first, second and third equivalence point, of a titration of triprotic acid and NaOH ? Pka 1= 3.128 Pka 2=4.761 Pka 3= 6.396 Concentration of acid : 0,026 M Volume of acid : 50 ml Concentration of NaOh = 99,986mM
Why is the pH of the first, second and third equivalence point, of a titration of triprotic acid and NaOH ? Pka 1= 3.128 Pka 2=4.761 Pka 3= 6.396 Concentration of acid : 0,026 M Volume of acid : 50 ml Concentration of NaOh = 99,986mM
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section17.3: Acid-base Titrations
Problem 2RC: 2. What is the pH at the equivalence point in the titration of 25.0 mL of 0.090 M phenol (Ka = 1.3 ×...
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Why is the pH of the first, second and third equivalence point, of a titration of triprotic acid and NaOH ?
Pka 1= 3.128
Pka 2=4.761
Pka 3= 6.396
Concentration of acid : 0,026 M
Volume of acid : 50 ml
Concentration of NaOh = 99,986mM
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