Why is it that the heat of condensation isn't negative along with the amount of heat released in the cooling of water? I thought Delta H con =(-Delta H vap?) Im not sure what I'm missing please help explain and break it down for me pictures help as well thank you so0o much! :) Part A Using the values for the heat of fusion, specific heat of water, and/or heat of vaporization, calculate the amount of heat energy in each of the following. Keep in mind that the sign of the heat involved in Calculate the joules released when 155 g of steam condenses at 100 °C and the liquid cools to 10.0 °C. the state change is ignored. Express your answer to three significant figures and include the appropriate units. Link to sample problems on phase change calculations. ? Value Units Submit Request Answer Rate an steam Condensation 1559 15 59 water waten Caling 100°C 1559 10.0°C 100°C AT Amount of Heat released in condensation (4)= (AH Mass ot steam %3D vep = (2259.36JA( 155 9) %3D 350200.8 T 3.50 X10° J Amount of Heat released in cooling of wader (Ha) = m.Sehe AT H2 = 5.83 X10 J H2 = 0.583 X10 J

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Why is it that the heat of condensation isn't
negative along with the amount of heat
released in the cooling of water? I thought
Delta H con =(-Delta H vap?) Im not sure
what I'm missing please help explain and
break it down for me pictures help as well
thank
you sooo much! :)
Part A
Using the values for the heat of fusion, specific heat
of water, and/or heat of vaporization, calculate the
amount of heat energy in each of the following.
Keep in mind that the sign of the heat involved in
Calculate the joules released when 155 g of steam condenses at 100 °C and the liquid cools to 10.0 °C.
the state change is ignored.
Express your answer to three significant figures and include the appropriate units.
Link to sample problems on phase change
calculations.
HÀ
?
Value
Units
Submit
Request Answer
Rate an
steam Condensation
155g
1559 water
10.0°C
1559
waten Caling
100°C
100°C
AT
Amount of Heat released in condensation(4)= (AH Mass ot steam
vep
= (2259.36 JA( 155 9)
%3D
%3D
350200.8 J
3.50 지0 J
Ameunt of Heat released in cooling of wake1( Ha) = m.Sei
Amount ot Heat released in
AT
(1539)(4.1474
H2 = 5.83 X10 J
H2 = 0.583 X10 J
Transcribed Image Text:Why is it that the heat of condensation isn't negative along with the amount of heat released in the cooling of water? I thought Delta H con =(-Delta H vap?) Im not sure what I'm missing please help explain and break it down for me pictures help as well thank you sooo much! :) Part A Using the values for the heat of fusion, specific heat of water, and/or heat of vaporization, calculate the amount of heat energy in each of the following. Keep in mind that the sign of the heat involved in Calculate the joules released when 155 g of steam condenses at 100 °C and the liquid cools to 10.0 °C. the state change is ignored. Express your answer to three significant figures and include the appropriate units. Link to sample problems on phase change calculations. HÀ ? Value Units Submit Request Answer Rate an steam Condensation 155g 1559 water 10.0°C 1559 waten Caling 100°C 100°C AT Amount of Heat released in condensation(4)= (AH Mass ot steam vep = (2259.36 JA( 155 9) %3D %3D 350200.8 J 3.50 지0 J Ameunt of Heat released in cooling of wake1( Ha) = m.Sei Amount ot Heat released in AT (1539)(4.1474 H2 = 5.83 X10 J H2 = 0.583 X10 J
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