The vapor pressure of ethanol is 100 mmHg at 34.9°C. What is its vapor pressure at 63.5 °C? (AHvap for ethanol = 39.3 kJ/mol) In P₁ P2 AHvap (1 R T₂ T₁ AHvap = 3.93 x 104 J/mol In P₁ = AHvap R P2 P₂ 2 P₁ = 100 mm Hg/760 mm Hg atm-1 = 0.1316 atm T₁ = 34.9 + 273.15 = 308.1 K T₂ = 63.5+ 273.15 = 336.7 K 1 - 1 T₂ T₁ 2 1 In 0.1316 = 3.93 x 104 1316 8.314 => P₂ = e-0.72477 P2 => 1 336.7 R = 8.314 J/mol K - 1 - 308.1 In (0.1316) - In(P₂) = 4.727 x 103 (-2.75697 x 10-4) -In(P₂) = 0.72477 => In(P₂) = -0.72477 => P₂ = 0.4844 atm = 368 mm Hg

The vapor pressure of ethanol is 100 mmHg at 34.9°C. What is its vapor pressure at 63.5 °C? (AHvap for ethanol = 39.3 kJ/mol) In P₁ P2 AHvap (1 R T₂ T₁ AHvap = 3.93 x 104 J/mol In P₁ = AHvap R P2 P₂ 2 P₁ = 100 mm Hg/760 mm Hg atm-1 = 0.1316 atm T₁ = 34.9 + 273.15 = 308.1 K T₂ = 63.5+ 273.15 = 336.7 K 1 - 1 T₂ T₁ 2 1 In 0.1316 = 3.93 x 104 1316 8.314 => P₂ = e-0.72477 P2 => 1 336.7 R = 8.314 J/mol K - 1 - 308.1 In (0.1316) - In(P₂) = 4.727 x 103 (-2.75697 x 10-4) -In(P₂) = 0.72477 => In(P₂) = -0.72477 => P₂ = 0.4844 atm = 368 mm Hg

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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