What amount of heat (in kJ) is required to convert 14.7 g of an unknown liquid (MM = 83.21 g/mol) at 19.2 °C to a gas at 93.5 °C? (specific heat capacity of liquid = 1.58 J/g °C; specific heat capacity of gas = 0.932 J/g °C; AHvap = 22.5 kJ/mol; normal boiling point, Tb = 57.3 °C)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question
**Problem Statement:**

*What amount of heat (in kJ) is required to convert 14.7 g of an unknown liquid (MM = 83.21 g/mol) at 19.2 °C to a gas at 93.5 °C?*

- Specific heat capacity of liquid = 1.58 J/g·°C
- Specific heat capacity of gas = 0.932 J/g·°C
- ΔHvap = 22.5 kJ/mol
- Normal boiling point, Tb = 57.3 °C

**Explanation of Terms:**

- **MM (Molar Mass):** The mass of one mole of a substance, provided as 83.21 g/mol.
- **Specific Heat Capacity:** The amount of heat required to raise the temperature of 1 gram of a substance by 1 °C. It is given for both the liquid and gas phases.
- **ΔHvap (Enthalpy of Vaporization):** The amount of heat required to convert one mole of a liquid into its vapor without a temperature change, provided as 22.5 kJ/mol.
- **Normal Boiling Point (Tb):** The temperature at which the liquid boils under a pressure of 1 atmosphere, given as 57.3 °C.

**Solution Approach:**

To solve this problem, you need to calculate the total heat required in three steps:

1. **Heating the Liquid from 19.2 °C to 57.3 °C (Boiling Point):**
   - Use the formula \( q = m \times c \times \Delta T \) where \( m \) is mass, \( c \) is specific heat capacity, and \( \Delta T \) is the change in temperature.
   
2. **Vaporizing the Liquid at Boiling Point:**
   - Use the formula \( q = n \times \Delta H_{vap} \) where \( n \) is the number of moles and \( \Delta H_{vap} \) is the enthalpy of vaporization.

3. **Heating the Gas from 57.3 °C to 93.5 °C:**
   - Again, use the formula \( q = m \times c \times \Delta T \).

Make sure the units are consistent throughout the calculations, converting grams to moles where necessary and joules to kilojoules for the final
Transcribed Image Text:**Problem Statement:** *What amount of heat (in kJ) is required to convert 14.7 g of an unknown liquid (MM = 83.21 g/mol) at 19.2 °C to a gas at 93.5 °C?* - Specific heat capacity of liquid = 1.58 J/g·°C - Specific heat capacity of gas = 0.932 J/g·°C - ΔHvap = 22.5 kJ/mol - Normal boiling point, Tb = 57.3 °C **Explanation of Terms:** - **MM (Molar Mass):** The mass of one mole of a substance, provided as 83.21 g/mol. - **Specific Heat Capacity:** The amount of heat required to raise the temperature of 1 gram of a substance by 1 °C. It is given for both the liquid and gas phases. - **ΔHvap (Enthalpy of Vaporization):** The amount of heat required to convert one mole of a liquid into its vapor without a temperature change, provided as 22.5 kJ/mol. - **Normal Boiling Point (Tb):** The temperature at which the liquid boils under a pressure of 1 atmosphere, given as 57.3 °C. **Solution Approach:** To solve this problem, you need to calculate the total heat required in three steps: 1. **Heating the Liquid from 19.2 °C to 57.3 °C (Boiling Point):** - Use the formula \( q = m \times c \times \Delta T \) where \( m \) is mass, \( c \) is specific heat capacity, and \( \Delta T \) is the change in temperature. 2. **Vaporizing the Liquid at Boiling Point:** - Use the formula \( q = n \times \Delta H_{vap} \) where \( n \) is the number of moles and \( \Delta H_{vap} \) is the enthalpy of vaporization. 3. **Heating the Gas from 57.3 °C to 93.5 °C:** - Again, use the formula \( q = m \times c \times \Delta T \). Make sure the units are consistent throughout the calculations, converting grams to moles where necessary and joules to kilojoules for the final
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 4 images

Blurred answer
Knowledge Booster
Ideal and Real Gases
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY