Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![1. Why is it necessary to allow enough time for your samples to dry?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1500f00d-ba9e-4c73-85c9-551267b6f6b7%2F7510f1a6-1e4f-468b-aace-6ab7188484df%2F0zi5zwr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Why is it necessary to allow enough time for your samples to dry?
![Excess H20 Added
Slow/Fast
Sample #
Starting Mass
Mass Recovered
М.Р.
(mL)
Crystallization
1
7 120-0- 120:5
0 42340 ।।१.१-1203.
slow
0.4186
2
0.5046g
fast
D.4920g
0:32429 la0:7- 1a1:3
Slow
4
0.4933g
fast
0.37089 1a1.9-122.7.
5
0:4910g
slow
D.3019g
122:0-122.7
D:5014g
fast
2.347291a.9-122-8
Observations:
• The
cooling
had a
lower range in companison to
the fast cooling.
slow
The
added, the nigher the
me Hing point ·
move
water that
was
Calculate the % recovery for each sample
= mass after
X 100
mass
before
#4) 0.37080g
#1) 0.41869
০ 44919
83.87%.
75.17%%
O.49339
#5) 0.30199
o 49109
61.49%0
#2) 0.42349
0.504169
83.91%0
#6) 0:34720g
6.5014g
69.25%0
#3) 0.3242g
O.49209
65.89%
LO](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1500f00d-ba9e-4c73-85c9-551267b6f6b7%2F7510f1a6-1e4f-468b-aace-6ab7188484df%2Fimwu94q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Excess H20 Added
Slow/Fast
Sample #
Starting Mass
Mass Recovered
М.Р.
(mL)
Crystallization
1
7 120-0- 120:5
0 42340 ।।१.१-1203.
slow
0.4186
2
0.5046g
fast
D.4920g
0:32429 la0:7- 1a1:3
Slow
4
0.4933g
fast
0.37089 1a1.9-122.7.
5
0:4910g
slow
D.3019g
122:0-122.7
D:5014g
fast
2.347291a.9-122-8
Observations:
• The
cooling
had a
lower range in companison to
the fast cooling.
slow
The
added, the nigher the
me Hing point ·
move
water that
was
Calculate the % recovery for each sample
= mass after
X 100
mass
before
#4) 0.37080g
#1) 0.41869
০ 44919
83.87%.
75.17%%
O.49339
#5) 0.30199
o 49109
61.49%0
#2) 0.42349
0.504169
83.91%0
#6) 0:34720g
6.5014g
69.25%0
#3) 0.3242g
O.49209
65.89%
LO
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