Why does the area get changed to .4 when that actualy area is 4m2? it is at the end of the equation.... d=v/a but under area it is .4... why not 4
Why does the area get changed to .4 when that actualy area is 4m2? it is at the end of the equation.... d=v/a but under area it is .4... why not 4
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Why does the area get changed to .4 when that actualy area is 4m2?
it is at the end of the equation....
d=v/a
but under area it is .4... why not 4
thanks
Transcribed Image Text:Given:
A boat (with a flat bottom) and its cargo weigh 5,000 N. The area of
the boat's bottom is 4 m?.
Concept Used:
The depth of the bottom of the boat can be calculated using the
following formula:
d =%
Where
d= Depth, V = Volume, A = Area
Volume of the boat inside the water is equal to the volume of water
displaced. Therefore, the volume of water displaced can be
calculated as follows:
V =
W
Where
V = Volume of water displaced
W = Total weight of boat and cargo
D = Density of water
g = Gravity
Transcribed Image Text:Calculation:
As per the given problem,
W = 5000 N
D = 1000 kg/m
g = 9.8 mls
A = 4 m?
Substituting the values of W, D and g in the following formula, we
get
V
V =
S000
1000x9.8
= V = 0.51 m
Substituting the value of V and A in the following formula, we get
d = %
051
d =
0.4
> d= 1.275 m
Conclusion:
The depth of the bottom of the boat = 1.275 m.
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