Please explain step by step VA+ Section1sectionPump efficiency (np) = 80%-Diameter (D)= GolmCalculatethepowerPompfor a pump / cup)3mAt SectionHeightabovePrec surfaceSection (2)V2= 2 m/sP2 = 150 kPaD2 = 0.065mZ₂=3m

The diameter of section 1 is d1=0.1 m. The diameter of section 2 is d2=0.065 m. The velocity in section 2 is V2=2 m/s. The pressure in section 2 is P2=150 kPa. The height above the free surface is h=3m. Applying the continuity equation Q=A1V1=A2V2 here A1=π*d124, A2=π*d224 The effective height H=h+V222g The power of the pump is given by the expression P=ρQgHηQ=π*d224*V2⇒Q=π*0.06524*2⇒Q=0.0066 m3/s H=h+V222g⇒H=3+222*9.81⇒H=3.20387 m P=ρQgHη⇒P=1000*0.0066*9.81*3.203870.8⇒P=259.297 W

Answered: A+ Section Section Pump efficiency (np)…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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V
A+ Section
1
section
Pump efficiency (np) = 80%-
Diameter (D)= Golm
Calculate
the
power
Pomp
for a pump / cup)
3m
At Section
Height
above
Prec surface
Section (2)
V2= 2 m/s
P2 = 150 kPa
D2 = 0.065m
Z₂=3m

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why did you neglect pressure at section 2? shouldn't that be taking into account when using the energy equation

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