Why did he take the average this way? He could just add all the numbers to each other than multiplies by their count. And when I did it I got a different answer. (10+15+13+9+32+10+25+0)/8= 6982.5. I would really appreciate an explanation.
Why did he take the average this way? He could just add all the numbers to each other than multiplies by their count. And when I did it I got a different answer. (10+15+13+9+32+10+25+0)/8= 6982.5. I would really appreciate an explanation.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Why did he take the average this way? He could just add all the numbers to each other than multiplies by their count. And when I did it I got a different answer. (10+15+13+9+32+10+25+0)/8= 6982.5. I would really appreciate an explanation.
Transcribed Image Text:AM
13cm
10cm 25cm
32cm
9cm
7 x 70cm
10cm 15cm
the scale is 1: 7,500
1CM on the map=7500 CM in arears
1CM=75CM
Step 2/4
(i) Average height rule:
Take average height of two sides for each area
10+15
h₂
h3
h₁
h5
h6
h7
=
2
15+13
2
13+9
2
9+32
2
32+10
2
10+25
2
25+0
2
= 12.5cm
= 14cm
11cm
20.5cm
= 21cm
= 17.5cm
12.5cm
therefore
total area in
cm² =
h₁ × 10 + h₂ × 10 + h3 × 10 + h4 × 10 + h5 × 10 + h6 × 10 + h7 × 10
area
= 12.5 x 70+ 14 x 70 + 11 × 70 + 20.5 x 70 + 21 x 70+ 17.5 × 70+ 12.5 × 70
area= 7,630cm²
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