√16+h-√√16 h = (√16+h-√16) (√16+h+√16 h(√16+h+√16) 16+h-16 h (√16+h+ √16) h h(√16+h+√16) 1 Vh + 16 + 4

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Could you just explain where 16+h-16 came from and how the h canceled out? Need to refresh my memory.

√16+h-√16
h
(√16+h-√16) (√16 +h+ √√16
h(√16+h+√16)
16+ h-16
h(√16+h+√16)
h
h(√16+h+ √ 16
1
√h + 16 + 4
Transcribed Image Text:√16+h-√16 h (√16+h-√16) (√16 +h+ √√16 h(√16+h+√16) 16+ h-16 h(√16+h+√16) h h(√16+h+ √ 16 1 √h + 16 + 4
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