while(!Q1.isEmpty()) 2 { 3 x = Q1.Dequeue(); 4 5▾ { 6 7 if (x == 1) z = 0; while(!S.isEmpty()) 8 - { 9 10 y = S.pop(); z = z + y; 11 } 12 Q2. Enqueue(z); 13 } 14 else 15 S.push(x); 16 } 17 Stack S; 18 Queue Q1, Q2; 19 int x, y, z; 20 Q1.Enqueue(9); 21 Q1.Enqueue(6); 22 Q1.Enqueue(9); 23 Q1.Enqueue(1); 24 Q1.Enqueue(7); 25 Q1.Enqueue(5); 26 Q1.Enqueue(1); 27 Q1.Enqueue(2); 28 Q1.Enqueue(8);

while(!Q1.isEmpty()) 2 { 3 x = Q1.Dequeue(); 4 5▾ { 6 7 if (x == 1) z = 0; while(!S.isEmpty()) 8 - { 9 10 y = S.pop(); z = z + y; 11 } 12 Q2. Enqueue(z); 13 } 14 else 15 S.push(x); 16 } 17 Stack S; 18 Queue Q1, Q2; 19 int x, y, z; 20 Q1.Enqueue(9); 21 Q1.Enqueue(6); 22 Q1.Enqueue(9); 23 Q1.Enqueue(1); 24 Q1.Enqueue(7); 25 Q1.Enqueue(5); 26 Q1.Enqueue(1); 27 Q1.Enqueue(2); 28 Q1.Enqueue(8);

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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bool validPassword=true; cin >> passPhrase;} if (passPhrase.length() <= 4) { validPassword = false; } else { int digitCount=0; for (int i = 0; i < passPhrase.length(); i++) { if (isdigit(passPhrase.at(i))) digitCount++; } if (digitCount > 4) { validPassword=false; } if (validPassword) { cout << "Valid" << endl; } else { cout << "Invalid" << endl; } return 0;} // it still comes up with these errors. Not sure what it is telling me. main.cpp:9:7: error: expected unqualified-id before ‘if’ 9 | if (passPhrase.length() <= 4) { | ^~ main.cpp:13:7: error: expected unqualified-id before ‘else’ 13 | else { | ^~~~
Suppose CalSomething is an overloaded method. The declarations of the CalSomething methods are shown below. Assume there is sensible code within the curly-brackets. 1. int CalSomething (int a) {. } 2. int CalSomething (int[] a) { .. } 3. int CalSomething (double a) ( } 4. int Calsomething (double[] a) ( - ) 5. int Calsomething (int a, int b)( - ) 6. int CalSomething (int a, double b) { . } 7. int CalSomething (double a, double b) ( .- } 8. int CalSomething (double a, int b, int c) { ... } 9. int CalSomething (int a, int b, double c) { .. } 10. int Calsomething (int a, int b, int c) { ... } 11. int CalSomething (int a, double b, int[] c) { ... } 12. No corresponding method definition Consider the snippet of code below... int a = 11, b = 22, c = 0; double x = 1.5, y = 5.8; int [] iarr = new int[99]; double [] darr = new double[99];
# hard-coded calls # hard-coded linescouple = NumCouple(4, 7)print(f"The couples minimum is {couple.minimum()}")print(f"The couples maximum is {couple.maximum()}")print(f"The couples product is {couple.product()}")thruple = NumThruple(3, 5, 2)print(f"The thruples minimum is {thruple.minimum()}")print(f"The thruples maximum is {thruple.maximum()}")print(f"The thruples product is {thruple.product()}")
Hi i need an implementation on the LinkListDriver and the LinkListOrdered for this output : Enter your choice: 1 Enter element: Mary List Menu Selections 1. add element 2_remove element 3.head element 4. display 5.Exit Enter your choice: 3 Element @ head: Mary List Menu Selections 1-add element 2-remove element 3_head element 4.display 5-Exit Enter your choice: 4 1. Mary List Menu Selections 1. add element 2. remove element 3.head element 4. display 5. Exit Enter your choice: LinkedListDriver package jsjf; import java.util.LinkedList; import java.util.Scanner; public class LinkedListDriver { public static void main(String [] args) { Scanner input = new Scanner(System.in); LinkedList list = new LinkedList(); int menu = 0; do { System.out.println("\nList menu selection\n1.Add element\n2.Remove element\n3.Head\n4.Display\n5.Exit"); System.out.println();…
Problem Description The hailstone sequence is defined as the integer sequence that results from manipulating a positive integer value n as follows: If n is even, divide it by 2 (using floor division) • If n is odd, multiply it by 3 and then add 1 Repeat this process until you reach 1. For example, starting with n = 5, we get the sequence 5, 16, 8, 4, 2, 1. If n is 6, we get the sequence 6, 3, 10, 5, 16, 8, 4, 2, 1. If n is 7, we get 7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1. If n is 8, we get the sequence 8, 4, 2, 1. As far as anyone can tell, this process will eventually reach 1 for any starting value, although mathematicians have been unable to formally prove this property as of yet. a. Write a Python function named hail () that takes a single integer argument. hail() should print out the sequence of numbers generated by applying the process above to the function parameter. This function does not return any value.
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Double any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner (System.in); final int NUM_POINTS = 4; int [] dataPoints new int [NUM_POINTS]; int controlValue; int i; controlValue = scnr. nextInt (); for (i = 0; i < dataPoints.length; ++i) { = scnr.nextInt (); dataPoints [i] } /* Your solution goes here * / for (i = 0; i < dataPoints.length; ++i) { System.out.print (dataPoints[i] + %3D " ") ; } System.out.println ();
class overload { int x; double y; void add(int a , int b) { x = a + b; } void add(double c , double d) { y = c + d; } overload() { this.x 0; %3D this.y = 0; } %3D } class Overload_methods { public static void main(String args[]) { overload obj int a = 2; double b - 3.2; obj.add(a, a); obj.add(b, b); System.out.println(obj.x + } = new overload(); + obj.y); } #3Run the code
/* * rotate4 - Rotate x to the left by 4 * Examples: rotate4(0x87654321) = 0x76543218 * Legal ops: ~ & ^ | + << >> ! * Max ops: 10 * Rating: 2 */int rotate4(int u) { return 2;} Do not use any control constructs such as if, do, while, for, switch, etc.
using System; class Program { publicstaticvoid Main(string[] args) { int number = 1,i; while (number <= 88) { Console.WriteLine(number); number = number + 2; { Random r = new Random(); int[] randNo=newint[3]; for(i=0;i<3;i++) { randNo[i]= r.Next(1,88) Console.WriteLine("Random Number between 1 and 88 is "+randNo); } } } } } how can this program be fixed to choose three random numbers in C# between 1-88 instead of just one random number?
public void actionPerformed(ActionEvent ae) {try {SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy", Locale.ENGLISH);Date lk1 = from.getDate();Date lk2 = to.getDate();long df = Math.abs(lk1.getTime() - lk2.getTime());long deiffrent = TimeUnit.DAYS.convert(df, TimeUnit.MILLISECONDS);day.setText(String.valueOf(deiffrent));if (day.getText().equals("")) {JOptionPane.showMessageDialog(null, "Day field is empty");return;} int days = Integer.parseInt(day.getText());if (numofroom.getText().equals("")) {JOptionPane.showMessageDialog(null, "Number of rooms field is empty");return;} int room = Integer.parseInt(numofroom.getText()); if (ae.getSource() == studio){ double f = room * 300 * days;String a = String.valueOf(f);double vat1 = f * 0.15;String b = String.valueOf(vat1);double total1 = f + vat1;String c = String.valueOf(total1);if (ae.getSource() == calculate) {ty.setText("STUDIO" + "," + lk1 + "," + lk2);subtotolfield.setText(a);vat_f.setText(b);totolfield.setText(c);}} else if…