While we are at it, let's do the same thing for the second step of the mechanism. Again, what is happening with the arrows circled in red below? Cys157 Cys157 Cys157 His296 His296 His296 он он „OH HN, HN HN CO2 CH2 Asn329N" Asn329 Asn329- Cys157 His296 LOH HNN Asn329N O deprotonation of the conjugate acid form of imidazole, followed by general base assistance in decarboxylation O nucleophilic addition of the cysteine side chain to imidazole O decarboxylation coupled with the generation of molecular hydrogen (H2) O general acid catalyzed isomerization covalent attachment of the substrate to the enzyme
While we are at it, let's do the same thing for the second step of the mechanism. Again, what is happening with the arrows circled in red below? Cys157 Cys157 Cys157 His296 His296 His296 он он „OH HN, HN HN CO2 CH2 Asn329N" Asn329 Asn329- Cys157 His296 LOH HNN Asn329N O deprotonation of the conjugate acid form of imidazole, followed by general base assistance in decarboxylation O nucleophilic addition of the cysteine side chain to imidazole O decarboxylation coupled with the generation of molecular hydrogen (H2) O general acid catalyzed isomerization covalent attachment of the substrate to the enzyme
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![While we are at it, let's do the same thing for the second step of the mechanism. Again, what is
happening with the arrows circled in red below?
Cys157
Cys157
Cys157
His296
His296
His296
OH
HO
HN,
N:
HN
HN
-CO2
CH2
he
Asn329
Asn329
Asn329-
Cys157
His296
LOH
LOH
HNNH
Asn329-
O deprotonation of the conjugate acid form of imidazole, followed by general base assistance in decarboxylation
nucleophilic addition of the cysteine side chain to imidazole
O decarboxylation coupled with the generation of molecular hydrogen (H2)
O general acid catalyzed isomerization
covalent attachment of the substrate to the enzyme](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2818b5ba-2148-47e4-9cd9-ed51e9e5ed65%2F8290145e-3814-43ed-9aef-3f357b48f085%2Fp7np7x_processed.png&w=3840&q=75)
Transcribed Image Text:While we are at it, let's do the same thing for the second step of the mechanism. Again, what is
happening with the arrows circled in red below?
Cys157
Cys157
Cys157
His296
His296
His296
OH
HO
HN,
N:
HN
HN
-CO2
CH2
he
Asn329
Asn329
Asn329-
Cys157
His296
LOH
LOH
HNNH
Asn329-
O deprotonation of the conjugate acid form of imidazole, followed by general base assistance in decarboxylation
nucleophilic addition of the cysteine side chain to imidazole
O decarboxylation coupled with the generation of molecular hydrogen (H2)
O general acid catalyzed isomerization
covalent attachment of the substrate to the enzyme
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