Answered: While the goal of hypothesis is to test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the likelihood ratio to finda 95% confidence interval for theta based on data in Table 5.1. Please look at this message and solve my question accordingly, don't just explain the images, I know what's going on in them. The past 2 times I've asked, no one's read my message.
Say that on average teenagers eat 10 slices of pizza each week, with a 95% confidence interval of (8-12). We take a sample of teenagers and find that this group eats an average of 6 slices each week. What can we say about the teenagers in the sample in relation to the confidence interval?
Let π denote some population proportion of interest and suppose a 99% confidence interval for π is calculated to be (0.60, 0.70). Also, suppose we want to test the hypotheses H0:π=0.74 and HA:π≠0.74 . What can you say about the corresponding p-value? The corresponding p-value will be smaller than 0.01. The corresponding p-value will be smaller than 0.05 but larger than 0.01. The corresponding p-value will be larger than 0.05. I can't say anything about the corresponding p-value until I run the test.
A study investigated ways to prevent staph infections in surgery patients. The researchers examined a random sample of 100 patients admitted to various hospitals for surgery. They found that 53 of these patients tested positive for Staphylococcus aureus, a bacterium responsible for most staph infections. Construct a 80% confidence interval for the proportion of all patients admitted for surgery who are carriers of S. aureus. Round your answers to three decimal places, and use four decimal places for any interim calculations. We are 80% confident that the interval ( of all patients admitted for surgery who are carriers of S. aureus. contains the true population proportion p
Assume that last year in a particular state there were 211 children out of 1990 who were diagnosed with Autism Spectrum Disorder. Nationally, 1 out of 88 children are diagnosed with ASD. It is believed that the incident of ASD is more common in that state than nationally. Calculate a 96% confidence interval for the percentage of children in that state diagnosed with ASD.P: Parameter What is the correct parameter symbol for this problem? What is the wording of the parameter in the context of this problem? A: Assumptions Since information was collected from each object, what conditions do we need to check? Check all that apply. n≥30n≥30 or normal population. N≥20nN≥20n n(pˆ)≥10n(p̂)≥10 σσ is known. σσ is unknown. n(1−pˆ)≥10n(1-p̂)≥10 Check those assumptions: 1. nˆpnp^= which is 2. n(1−ˆp)n(1-p^)= which is 3. NN= which is If no N is given in the problem, use 1000000N: Name the procedure The…
A researcher wants to estimate the true proportion of Americans who suffer side-effects after taking a particular medication. A 99% confidence interval for the true proportion of Americans who suffer side-effects after taking the particular medication was found to be (0.024, 0.160). If a hypothesis test is conducted with the hypotheses, H,: p = 0.10 vs H: p# 0.10 , what would be the most likely conclusion? Select one: a. There is very strong evidence that p 0.10. Ob. There is little to no evidence that p = 0.10. c. There is little to no evidence that p # 0.10. d. Cannot tell.
(2) Maximum likelihood estimators are unbiased. True False
The national average for the percentage of high school graduates taking the SAT is 49%, but the state averages vary from a low of 4% to a high of 92%. A random sample of 317 graduating high school seniors was polled across a particular tristate area, and it was found that 171 had taken the SAT. Estimate the lower boundary of the true proportion of high school graduates in this region who take the SAT with 95% confidence. Only the final answer should be rounded-off to THREE decimal places.
A random sample of 212 high school students in a particular town showed that 56 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school. Suppose the national average for smokers in high schools is 34.2%. Does it appear that the students in this particular town smoke less than the national average? Justify your answer
On average, 0(zero) is expected for the t statistic when the null hypothesis is true. Why? The value for an unknown population mean is estimated with a confidence interval using the t statistic? Why?
Two researchers, Jaime and Mariya, are each constructing confidence intervals for the proportion of a population who is lef-handed. They find the point estimate is 0.23. Each independently constructed a confidence interval based on the point estimate, but Jaime's interval has a lower bound of 0.220 and an upper bound of 0.234, while Mariya's interval has a lower bound of 0.169 and an upper bound of 0.272. Which interval is wrong? Why? 28 Choose the correct answer below. OA Jaime's interval is wrong because it does not include the point estimate. OB. Mariya's interval is wrong because it is too wide. OC. Mariya's interval is wrong because it is not centered on the point estimate, OD. Jaime's interval is wrong because it is to narrow O of 36
Let p equal the proportion of athletes who suffered a training-related overuse injury during the past year. Out of 330 athletes who responded to a survey, 167 indicated that they had suffered such an injury during the past year. (a) Use these data to give a point estimate of p. (b) Use these data to find an approximate 90% confidence interval for p. (c) Some researchers claim that the injury rate should be less than 0.4. Please test the hypothesis: H0: p=0.4 vs p

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While the goal of hypothesis is to test a claim (against Ho), the goal of confidence interval estimation is to estimate a parameter. True False