Ferulic acid is a compound that may play a role in disease resistance in corn.. A botanist measured theconcentration of soluble ferulic acid (nmol acid per gm tissue) in corn seedlings grown in the dark or in alight/dark photoperiod. The data are shown in the table below:Sample 1: Dark9211788911071091001018787Sample 2:Photoperiod111127104115129124123121120117 Which of the following are true based on the 95% confidence interval constructed in the previous problem?We are 95% confident that the population mean for corn seedlings grown in the light/dark photoperiod islarger than that for corn seedlings grown in the dark.We are 95% confident that the sample mean difference in the concentration of soluble ferulic acid betweencorn seedlings grown in a light/dark photoperiod and corn seedlings grown in the dark is between -29.9 and-12.5 nmol acid per gm tissue.We are 95% confident that the population mean difference in the concentration of soluble ferulic acid betweencorn seedlings grown in the dark and corn seedlings grown in a light/dark photoperiod is between -29.9 and-12.5 nmol acid per gm tissue.We are 95% confident that the population mean concentration of soluble ferulic acid between corn seedlingsgrown in a light/dark photoperiod is at least 12.5 and at most 29.9 nmol acid per gm tissue greater than cornseedlings grown in the dark.

Given information: The two sample data are given below. Sample 1 Dark Sample 2 Photoperiod 92…

Answered: Which of the following are true based…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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20% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 356 randomly selected students who receive financial aid, 61 of them volunteered their time. What can be concluded at the αα = 0.10 level of significance? For this study, we should use? Select an answer z-test for a population proportion? or t-test for a population mean? The null and alternative hypotheses would be: H0:H0:? μ or p Select an answer ≥ = < > ≤ ≠ _______(please enter a decimal) H1:H1:? μ or p Select an answer ≥ ≠ = < > ≤ _______ (Please enter a decimal) 2. The test statistic ? t or z = ______ (please show your answer to 3 decimal places.) The p-value = ______ (Please show your answer to 4 decimal places.) The p-value is ? > or ≤ α 3. Based on this, we should Select an answer fail to reject? reject ? accept ? the null…
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65-74 years: n = 113, x = 12.4, and s = 6.63. Does this data indicate that average daily zinc intake in the population of all males age 65-74 falls below the recommended allowance? (Use a = 0.05.) State the appropriate null and alternative hypotheses. O Ho: H = 15 H: u > 15 O Ho: H = 15 H: u < 15 Ο H: μ15 H:us 15 Ο Η: μ- 15 H: u = 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = p-value = State the conclusion in the problem context. O Reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. O Do not reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. O Do not reject the null hypothesis. There…
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20.19- 20.24
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