USA Today (February 16, 2012) reported that the percentage of U.S. residents living in poverty was 12.5% for men and 15.1% for women. These percentages were estimates based on data from large representative samples of men and women. For purposes of this exercise, suppose that the sample sizes were 1200 for the sample of men and 1000 for the sample of women. Use the survey data to compute a 90% confidence interval for the difference in the proportion living in poverty for men and women. (Use p Round your answers to men - Pwomen' three decimal places.) ( Interpret the interval. There is a 90% chance that the true mean proportion living in poverty for men is directly in the middle of these two values. We are 90% confident that the true mean proportion living in poverty for women is between these two values. We are 90% confident that the true difference in the proportions living in poverty for men and women is between these two values. We are 90% confident that the true mean proportion living in poverty for men is between these two values. O There is a 90% chance that the true difference in the proportions living in poverty for men and women is directly in the middle of these two values.