While( n >1 ) System.out.println ("hello"); n=n/2; } O 0(1) O O(n) O O(logn) O On?)
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- PLEASE HELP!method SumTon(n:int) returns (s:int) requires n > = 0 ensures s = = n*(n+1)/2 // THE = (k-1)*k FORMULA! { var k: = 0; s: = 0; while k <= n invariant 0 < = k < = n+1 && S = /2 {s:= s + k; k: = k + 1; } //1A!B=s= = (k-1)*k/2 && k = = n+1 = postcondition } Using this method as starting point, change the method so that the loop instead `iterates down' from n to 0. You should continue to use just one local variable as index (stay in the spirit of this exercise). The method should continue to verify of course. Call the new method SumTonDown. =Trace the following code and write what it does. void Finals(X, Y, m, n) { int i=1, j-1, k=13; while (i <=m && j<=n) { if (X[i]Find the values of n and m to solve this puzzle int n = ? int m = ? int t = 76; int s = 0; char *msg = "Do you like spaghetti? Try some spaghetti! It's good, right?\n" "What, you prefer structured loops? How mundane.\n"; goto LTOP; LEND: failure(msg); LOM1: n = (n<<2) - n + 1; LCHK: if(s == t && m == t){ goto LAFT; } s++; goto LTOP; LOC1: if(n & 1){ goto LOM1; } goto LEM1; LTOP: if(!(n>1)){ goto LEND; } goto LOC1; LEM1: n = n >> 1; goto LCHK; LAFT: return;def hailstone(n): h.append(int(n)) if n == 1: return h while n != 1: if n % 2 == 0: return hailstone(int(n/2)) else: return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0: print("N must be positive!")else: print("Hailstone sequences for 1 to " + str(y) + ":") m=0; i=1 for x in range(1, y+1): n = i h = [] h = hailstone(n) print(h) s=len(h) if s > m: m=s flag=n i=i+1 print("First longest sequence found in n =", + flag ) If i don't one the output have the square braket? How can I fix this code? Can you pleasw help me?What is the value of the variable ss after the following code is executed? int x[ 7 ] = (5,10,3,0,-10, 4); int ss=0; for (int i=1;i<=6; i++) { ss+=x[i]; cout<def hailstone(n): h.append(int(n)) if n == 1: return h while n != 1: if n % 2 == 0: return hailstone(int(n/2)) else: return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0: print("N must be positive!")else: print("Hailstone sequences for 1 to " + str(y) + ": ") m=0; i=1 for x in range(1, y+1): n = i h = [] h = hailstone(n) print(*h) print(",") s=len(h) if s > m: m=s flag=n i=i+1 print("First longest sequence found in n =", + flag ) How can I fix this code if I want a comma between each number, not each line?a) Write a recursive method that calculates the following series:F(n)= (??+Σ?)??=1*(??+Σ?)?/??=1*(??+Σ?)?/??=1*(??+Σ?)?/??=1*….*2b) Write the recurrence expression T(n).Generate test cases for the following code by using basic path testing. a) Draw CFG. c) d) int test_prime() { int x=1,n,i; } How many basic paths for the CFG? List the basic paths. Generate test cases from it. } scanf("%d",&n); if(n==2) else printf("prime"); for(i=2;iWhat does the following code do? In [1]: def mystery (a, b) : if b == 1: return a else: return a + mystery (a, b - 1) In [2]: mystery (2, 10) Out [2]: ?????Does the following code snippet grow linearly? for(int i = n; i > n/2; i--); True False Question 8What is the value of the variable ss after the following code is executed? int x[ 7 ] = (5,10,3,0,-10, 4); int ss=0; for (int i=1;i<=6; i++) { ss+=x[i]; cout<SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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