While investigating the properties of other diatomic molecules, the student finds the diagram below, which shows the potential energy of two iodine atoms versus the distance between their nuclei. The student also finds that the I - I bond energy is slightly less than the F – F bond energy. The student incorrectly sketches the potential energy curve for two fluorine atoms, shown by the dotted line in the diagram. 200- 100- E一 200 600 1100 300 400 500 700 800 -100+ -200- Internuclear Distance (pm) (h) Explain the error with the student's sketch for F2(g). Potential Energy (kJ/mol)

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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While investigating the properties of other diatomic molecules, the student finds the diagram below, which shows the potential energy of two iodine atoms versus the distance between their nuclei. The student also finds
that the I- I bond energy is slightly less than the F – F bond energy. The student incorrectly sketches the potential energy curve for two fluorine atoms, shown by the dotted line in the diagram.
200
100
200
600
300.
400 500
1100
700 800
-100
-200
Internuclear Distance (pm)
(h) Explain the error with the student's sketch for F2(g).
Potential Energy (kJ/mol)
Transcribed Image Text:While investigating the properties of other diatomic molecules, the student finds the diagram below, which shows the potential energy of two iodine atoms versus the distance between their nuclei. The student also finds that the I- I bond energy is slightly less than the F – F bond energy. The student incorrectly sketches the potential energy curve for two fluorine atoms, shown by the dotted line in the diagram. 200 100 200 600 300. 400 500 1100 700 800 -100 -200 Internuclear Distance (pm) (h) Explain the error with the student's sketch for F2(g). Potential Energy (kJ/mol)
An unknown gas, D, reacts with fluorine gas to form the compound DF4(g), as represented by the following equation.
D(g) + 2 F2(9) → DF4(9)
A series of experimental trials were performed at 600°C to determine the rate law expression for the reaction. Data from the trials are shown below.
Initial Pp
Initial PF2
Initial Rate of Appearance of DF,(9)
(torr)
(torr)
(torr/min)
Trial 1
1500
1500
5.00 x 10–3
Trial 2
3000
1500
10.0 x 10-3
Trial 3
1500
3000
20.0 x 10–3
Transcribed Image Text:An unknown gas, D, reacts with fluorine gas to form the compound DF4(g), as represented by the following equation. D(g) + 2 F2(9) → DF4(9) A series of experimental trials were performed at 600°C to determine the rate law expression for the reaction. Data from the trials are shown below. Initial Pp Initial PF2 Initial Rate of Appearance of DF,(9) (torr) (torr) (torr/min) Trial 1 1500 1500 5.00 x 10–3 Trial 2 3000 1500 10.0 x 10-3 Trial 3 1500 3000 20.0 x 10–3
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