While doing her crossfit workout, Yasmeen holds an 7.0 kg weight at arm's length, a distance of 0.57 m from her shoulder joint. What is the torque about her shoulder joint due to the weight if her arm is horizontal? A. 30 N.m B. 4.0 N.m C. 43 N.m D. 39 N.m OB O C O A OD
While doing her crossfit workout, Yasmeen holds an 7.0 kg weight at arm's length, a distance of 0.57 m from her shoulder joint. What is the torque about her shoulder joint due to the weight if her arm is horizontal? A. 30 N.m B. 4.0 N.m C. 43 N.m D. 39 N.m OB O C O A OD
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
While doing her crossfit workout, Yasmeen holds a 7.0 kg weight at arm's length, a distance of 0.57 m from her shoulder joint. What is the torque about her shoulder joint due to the weight if her arm is horizontal?
**Options:**
- A. 30 N · m
- B. 4.0 N · m
- C. 43 N · m
- D. 39 N · m
**Answer Choices:**
- ○ B
- ○ C
- ○ A
- ○ D
**Explanation:**
To solve for the torque, use the formula:
\[ \text{Torque} = \text{Force} \times \text{Distance} \]
Where the force is the weight of the object, calculated as:
\[ \text{Force} = \text{mass} \times \text{gravity} = 7.0 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 68.6 \, \text{N} \]
Thus, the torque is:
\[ \text{Torque} = 68.6 \, \text{N} \times 0.57 \, \text{m} = 39.1 \, \text{N} \cdot \text{m} \]
The correct answer is closest to option D. 39 N · m.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab8e90de-1834-4897-8d02-45bfaff51002%2Fe940c460-0118-42b3-ad8a-7f0d8a6342a7%2Frhmhp3v_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
While doing her crossfit workout, Yasmeen holds a 7.0 kg weight at arm's length, a distance of 0.57 m from her shoulder joint. What is the torque about her shoulder joint due to the weight if her arm is horizontal?
**Options:**
- A. 30 N · m
- B. 4.0 N · m
- C. 43 N · m
- D. 39 N · m
**Answer Choices:**
- ○ B
- ○ C
- ○ A
- ○ D
**Explanation:**
To solve for the torque, use the formula:
\[ \text{Torque} = \text{Force} \times \text{Distance} \]
Where the force is the weight of the object, calculated as:
\[ \text{Force} = \text{mass} \times \text{gravity} = 7.0 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 68.6 \, \text{N} \]
Thus, the torque is:
\[ \text{Torque} = 68.6 \, \text{N} \times 0.57 \, \text{m} = 39.1 \, \text{N} \cdot \text{m} \]
The correct answer is closest to option D. 39 N · m.

Transcribed Image Text:**Question:**
If the maximum stress in the elastic limit for a piece of plastic is 350 MPa (mega-Pascals), what will happen to the plastic after it is subjected to a 355 MPa stress?
**Options:**
A. It will permanently deform.
B. It will return to its original shape.
C. It will fracture.
D. It depends on the strain.
**Answer Choices:**
- ○ C
- ○ B
- ○ D
- ○ A
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