Calculate the torque about the origin if a force, F = (42 - 33 + 2k) N, acts on a particle located at 7 = (32 +23 - 1k)m. O.(+23-1k) N. m O (12-103-17k) N.m O (32-23-1k) N.m (32 +93 +12k) N.m
Calculate the torque about the origin if a force, F = (42 - 33 + 2k) N, acts on a particle located at 7 = (32 +23 - 1k)m. O.(+23-1k) N. m O (12-103-17k) N.m O (32-23-1k) N.m (32 +93 +12k) N.m
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Transcribed Image Text:**Calculate the Torque About the Origin**
Given:
- A force **F** = (4**i** - 3**j** + 2**k**) N
- A particle located at **r** = (3**i** + 2**j** - 1**k**) m
**Question:** Calculate the torque about the origin.
**Choices:**
- **(A)** ( **i** + 2**j** - 1**k** ) N·m
- **(B)** ( 1**i** - 10**j** - 17**k** ) N·m
- **(C)** ( 3**i** - 2**j** - 1**k** ) N·m
- **(D)** ( 3**i** + 9**j** + 12**k** ) N·m
**Detailed Explanation of Diagrams:**
There are no graphs or diagrams in the given image.
For educational purposes, to calculate the torque **τ** about the origin, you need to take the cross product of **r** and **F**:
**τ** = **r** × **F**
For the vectors:
**r** = (3, 2, -1)
**F** = (4, -3, 2)
The cross product formula for two vectors **r** = (r₁, r₂, r₃) and **F** = (F₁, F₂, F₃) is given by:
τ = (r₂F₃ - r₃F₂) **i** - (r₁F₃ - r₃F₁) **j** + (r₁F₂ - r₂F₁) **k**
Substituting in the given values:
τ = (2*2 - (-1)*(-3)) **i** - (3*2 - (-1)*4) **j** + (3*(-3) - 2*4) **k**
τ = (4 - 3) **i** - (6 - (-4)) **j** + ((-9) - 8) **k**
τ = 1 **i** - 10 **j** - 17 **k**
So the correct answer is:
- **(B)** (1**i** -
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