Which substance is serving as the reducing agent in the following reaction? 14H* (aq) + Cr20,2-(aq) + 3Ni(s) 3NI2*(aq) + 2Cr3-(aq) + 7H20() Select one: O a. Ni O b. H*(aq). O c. Cr20,2-(aq) O d. H20() O e. Ni2+
Which substance is serving as the reducing agent in the following reaction? 14H* (aq) + Cr20,2-(aq) + 3Ni(s) 3NI2*(aq) + 2Cr3-(aq) + 7H20() Select one: O a. Ni O b. H*(aq). O c. Cr20,2-(aq) O d. H20() O e. Ni2+
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Understanding Redox Reactions: Identifying the Reducing Agent
In the given chemical reaction, we need to identify which substance is acting as the reducing agent. The reaction is as follows:
\[ 14H^+(aq) + Cr_2O_7^{2-}(aq) + 3Ni(s) \rightarrow 3Ni^{2+}(aq) + 2Cr^{3+}(aq) + 7H_2O(l) \]
**Question:** Which substance is serving as the reducing agent in the following reaction?
**Options:**
- (a) Ni
- (b) H\(^+\)(aq)
- (c) Cr\(_2\)O\(_7\)^{2-}(aq)
- (d) H\(_2\)O(l)
- (e) Ni^{2+}
### Explanation:
To determine the reducing agent, we need to identify which substance is losing electrons (undergoing oxidation) in the reaction.
1. **Nickel (Ni):**
- Nickel starts off in its solid form (Ni) and ends up as Ni^{2+}(aq).
- This indicates it has lost electrons, following the half-reaction: Ni \(\rightarrow\) Ni^{2+} + 2e\(^-\).
- Losing electrons means it is being oxidized.
2. **Chromate Ion (Cr\(_2\)O\(_7\)^{2-}):**
- The chromate ion (Cr\(_2\)O\(_7\)^{2-}) is reduced to Cr^{3+}.
- This indicates it is gaining electrons, following the half-reaction: Cr\(_2\)O\(_7\)^{2-} + 14H\(^+\) + 6e\(^-\) \(\rightarrow\) 2Cr^{3+} + 7H\(_2\)O.
- Gaining electrons means it is being reduced.
Given that Nickel (Ni) is being oxidized, it serves as the reducing agent.
**Correct Answer:**
- (a) Ni
This explanation is intended to help students understand the principle of identifying reducing agents in redox reactions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6441173a-0d65-4fbd-a72a-c88019a4dfc8%2Fc5bef8e7-fced-471e-89d7-c1367dcad80a%2F1y2eh5r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Redox Reactions: Identifying the Reducing Agent
In the given chemical reaction, we need to identify which substance is acting as the reducing agent. The reaction is as follows:
\[ 14H^+(aq) + Cr_2O_7^{2-}(aq) + 3Ni(s) \rightarrow 3Ni^{2+}(aq) + 2Cr^{3+}(aq) + 7H_2O(l) \]
**Question:** Which substance is serving as the reducing agent in the following reaction?
**Options:**
- (a) Ni
- (b) H\(^+\)(aq)
- (c) Cr\(_2\)O\(_7\)^{2-}(aq)
- (d) H\(_2\)O(l)
- (e) Ni^{2+}
### Explanation:
To determine the reducing agent, we need to identify which substance is losing electrons (undergoing oxidation) in the reaction.
1. **Nickel (Ni):**
- Nickel starts off in its solid form (Ni) and ends up as Ni^{2+}(aq).
- This indicates it has lost electrons, following the half-reaction: Ni \(\rightarrow\) Ni^{2+} + 2e\(^-\).
- Losing electrons means it is being oxidized.
2. **Chromate Ion (Cr\(_2\)O\(_7\)^{2-}):**
- The chromate ion (Cr\(_2\)O\(_7\)^{2-}) is reduced to Cr^{3+}.
- This indicates it is gaining electrons, following the half-reaction: Cr\(_2\)O\(_7\)^{2-} + 14H\(^+\) + 6e\(^-\) \(\rightarrow\) 2Cr^{3+} + 7H\(_2\)O.
- Gaining electrons means it is being reduced.
Given that Nickel (Ni) is being oxidized, it serves as the reducing agent.
**Correct Answer:**
- (a) Ni
This explanation is intended to help students understand the principle of identifying reducing agents in redox reactions.
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