Chloride ions are added to the Ag|Ag* half-cell of the cell Ag|Ag*||Cu2|Cu to precipitate AgCl (s). The cell voltage is then measured to be +0.072 V at 298 K. If [Cu²*] = 1.0 M in the Cu2+|Cu half cell, what is [Ag*] in the Ag|Ag* half-cell? (First step: You will need to use the data in Table 17-1 to calculate E'cell.) Give your answer to two significant figures. Ecell = E°cell - (0.0257 V/n) In(Q) E'cell = E'ox + E°red
Chloride ions are added to the Ag|Ag* half-cell of the cell Ag|Ag*||Cu2|Cu to precipitate AgCl (s). The cell voltage is then measured to be +0.072 V at 298 K. If [Cu²*] = 1.0 M in the Cu2+|Cu half cell, what is [Ag*] in the Ag|Ag* half-cell? (First step: You will need to use the data in Table 17-1 to calculate E'cell.) Give your answer to two significant figures. Ecell = E°cell - (0.0257 V/n) In(Q) E'cell = E'ox + E°red
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Chloride ions are added to the AglAg* half-cell of the cell
Ag|Ag*l|Cu²*|Cu to precipitate AgCI (s). The cell voltage is then
measured to be +0.072 V at 298 K. If [Cu2+] = 1.0 M in the Cu2+|Cu half
cell, what is [Ag*] in the Ag|Ag* half-cell? (First step: You will need to
use the data in Table 17-1 to calculate E°cell.) Give your answer to
two significant figures.
Ecell = E°cell - (0.0257 V/n) In(Q)
E'cell = E°ox + E°red](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3e68242-5a91-4b54-b664-0ff90b744d38%2Fe5a5188e-682d-4f6f-b1ad-9145f22a7445%2Fseyjhck_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Chloride ions are added to the AglAg* half-cell of the cell
Ag|Ag*l|Cu²*|Cu to precipitate AgCI (s). The cell voltage is then
measured to be +0.072 V at 298 K. If [Cu2+] = 1.0 M in the Cu2+|Cu half
cell, what is [Ag*] in the Ag|Ag* half-cell? (First step: You will need to
use the data in Table 17-1 to calculate E°cell.) Give your answer to
two significant figures.
Ecell = E°cell - (0.0257 V/n) In(Q)
E'cell = E°ox + E°red
![cidic Solution, [H+] = 1M
CIO-(aq) + H2O + 2e-
Lit(aq) + e-
K+(aq) + e-
Ba2+(aq) + 2e-
Ca2+(aq) + 2e-
Na+(aq) + e-
Mg2+(aq) + 2e-
Al3+(aq) + 3e-
Mn2+(aq) + 2e
Zn2+(aq) + 2e-
Cr3+(aq) + 3e-
Fe2+(aq) + 2e-
Cr3+(aq) + e-
Cd2+(aq) + 2e-
PBSO4(s) + 2e-
TI+(aq) + e-
Co2+(aq) + 2e-
Ni2+(aq) + 2e-
Agl(s) + e-
Sn2+(aq) + 2e-
Pb2+(aq) + 2e-
2H+(aq) + 2e-
AgBr(s) + e-
S(s) + 2H+(aq) + 2e-
Sn4+(aq) + 2e-
SO.2-(aq) + 4H*(aq) + 2e-
Efed (V)
Li(s)
→K(s)
Ba(s)
→Ca(s)
Na(s)
→Mg(s)
Al(s)
→Mn(s)
→Zn(s)
Cr(s)
Fe(s)
Cr2+(aq)
Cd(s)
-3.040
Lithium is the strongest reducin
-2.936
-2.906
-2.869
-2.714
-2.357
-1.68
-1.182
-0.762
-0.744
-0.409
-0.408
-0.402
Pb(s) + SO,2-(aq)
TI(s)
Co(s)
Ni(s)
Ag(s) + 1-(aq)
Sn(s)
Pb(s)
-0.356
-0.336
->
-0.282
-0.236
-0.152
-0.141
-0.127
H2(g)
Ag(s) + Br(aq)
H2S(aq)
Sn2+(aq)
→SO2(g) + 2H2O
Cu*(aq)
Cu(s)
Cu(s)
21-(aq)
Fe2+(aq)
2Hg(1)
>Ag(s)
Hg2+(aq)
NO(g) + 2H20
→Au(s) + 4CI-(aq)
2Br(aq)
R
O = strongest oxidiz
0.000
R = strongest reduc
0.073
0.144
0.154
Cu2+(aq) + e-
Cu2+(aq) +.2e-
Cut(aq) + e-.
2(s) + 2e-
Fe3+ (aq).+ e-
Hg2 2+(aq) + 2e-
Ag+(aq) + e-
2H92+(aq) + 2e-
NO3-(aq) + 4H+(aq) + 3e-
AuCla-(aq) + 3e-
Br2(1) + 2e-
O2(g) + 4H+(aq) + 4e-
MnO2(s) + 4H+(aq) + 2e-
Cr20,2-(aq) + 14H+(aq) + 6e-
Cl2(g) + 2e-
CIO3-(aq) + 6H*(aq) + 5e¬
Au3+(ag) + Зе-
MnO4 (aq) + 8H+(aq) + 5e-
PbO2(s) + SO,2-(aq) + 4H*(aq) + 2e-
H2O2(aq) + 2H+(aq) + 2e-
Co3+ (aq) + e-
F2(g) + 2e-
0.155
->
0.161
0.339
0.518
0.534
0.769
0.796
0.799
0.908
0.964
1.001
1.077
2H20
1.229
1.229
→MN2+(aq) + 2H20
→2Cr3+(aq) + 7H20
→2CI-(aq)
Cb(g) + 3H20
Au(s)
Mn2+(aq) + 4H2O
PbSO4(s) + 2H2O
→2H20
Co2+(aq)
2F-(aq)
1.33
1.360
1.458
ban
1.498
1.512
1.687
1.763
1.953
2.889
Fluorine is the strongest c
Basic Solution, [OH-] = 1M
Efed (V)
-0.891
→Fe(s) + 20H-(aq)
→H2(g) + 20H-(aq)
Fe(OH)2(s) + OH-(aq)
-0.828
Fe(OH)2(s) + 2e-
2H20 + 2e-
Fe(OH)3(s) + e-
S(s) + 2e-
NO3-(ag) + 2H2O + 3e-
NO3 (ag) + H2O + 2e-
ClO4 (ag) + H2O + 2e
O>(g) + 2H20 + 4e-
CIo3 (ag) + 3H20+6e
-0.547
-0.445
Lithium and fluorine ard
ous materials to work
-0.140
NO(g) + 40H-(aq)
NO2 (aq) + 20H-(aq)
ClO, (aq) + 20H-(aq)
→4OH-(aq)
CI-(aq) + 60H-(aq)
CI-(aq) + 20H-(aq)
0.004
0.398
0.401
0.614
0.890
STANDARD
17.2
Increasing strength of oxidizing agents
Increasing strength of reducing agents](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3e68242-5a91-4b54-b664-0ff90b744d38%2Fe5a5188e-682d-4f6f-b1ad-9145f22a7445%2Fyttja83_processed.jpeg&w=3840&q=75)
Transcribed Image Text:cidic Solution, [H+] = 1M
CIO-(aq) + H2O + 2e-
Lit(aq) + e-
K+(aq) + e-
Ba2+(aq) + 2e-
Ca2+(aq) + 2e-
Na+(aq) + e-
Mg2+(aq) + 2e-
Al3+(aq) + 3e-
Mn2+(aq) + 2e
Zn2+(aq) + 2e-
Cr3+(aq) + 3e-
Fe2+(aq) + 2e-
Cr3+(aq) + e-
Cd2+(aq) + 2e-
PBSO4(s) + 2e-
TI+(aq) + e-
Co2+(aq) + 2e-
Ni2+(aq) + 2e-
Agl(s) + e-
Sn2+(aq) + 2e-
Pb2+(aq) + 2e-
2H+(aq) + 2e-
AgBr(s) + e-
S(s) + 2H+(aq) + 2e-
Sn4+(aq) + 2e-
SO.2-(aq) + 4H*(aq) + 2e-
Efed (V)
Li(s)
→K(s)
Ba(s)
→Ca(s)
Na(s)
→Mg(s)
Al(s)
→Mn(s)
→Zn(s)
Cr(s)
Fe(s)
Cr2+(aq)
Cd(s)
-3.040
Lithium is the strongest reducin
-2.936
-2.906
-2.869
-2.714
-2.357
-1.68
-1.182
-0.762
-0.744
-0.409
-0.408
-0.402
Pb(s) + SO,2-(aq)
TI(s)
Co(s)
Ni(s)
Ag(s) + 1-(aq)
Sn(s)
Pb(s)
-0.356
-0.336
->
-0.282
-0.236
-0.152
-0.141
-0.127
H2(g)
Ag(s) + Br(aq)
H2S(aq)
Sn2+(aq)
→SO2(g) + 2H2O
Cu*(aq)
Cu(s)
Cu(s)
21-(aq)
Fe2+(aq)
2Hg(1)
>Ag(s)
Hg2+(aq)
NO(g) + 2H20
→Au(s) + 4CI-(aq)
2Br(aq)
R
O = strongest oxidiz
0.000
R = strongest reduc
0.073
0.144
0.154
Cu2+(aq) + e-
Cu2+(aq) +.2e-
Cut(aq) + e-.
2(s) + 2e-
Fe3+ (aq).+ e-
Hg2 2+(aq) + 2e-
Ag+(aq) + e-
2H92+(aq) + 2e-
NO3-(aq) + 4H+(aq) + 3e-
AuCla-(aq) + 3e-
Br2(1) + 2e-
O2(g) + 4H+(aq) + 4e-
MnO2(s) + 4H+(aq) + 2e-
Cr20,2-(aq) + 14H+(aq) + 6e-
Cl2(g) + 2e-
CIO3-(aq) + 6H*(aq) + 5e¬
Au3+(ag) + Зе-
MnO4 (aq) + 8H+(aq) + 5e-
PbO2(s) + SO,2-(aq) + 4H*(aq) + 2e-
H2O2(aq) + 2H+(aq) + 2e-
Co3+ (aq) + e-
F2(g) + 2e-
0.155
->
0.161
0.339
0.518
0.534
0.769
0.796
0.799
0.908
0.964
1.001
1.077
2H20
1.229
1.229
→MN2+(aq) + 2H20
→2Cr3+(aq) + 7H20
→2CI-(aq)
Cb(g) + 3H20
Au(s)
Mn2+(aq) + 4H2O
PbSO4(s) + 2H2O
→2H20
Co2+(aq)
2F-(aq)
1.33
1.360
1.458
ban
1.498
1.512
1.687
1.763
1.953
2.889
Fluorine is the strongest c
Basic Solution, [OH-] = 1M
Efed (V)
-0.891
→Fe(s) + 20H-(aq)
→H2(g) + 20H-(aq)
Fe(OH)2(s) + OH-(aq)
-0.828
Fe(OH)2(s) + 2e-
2H20 + 2e-
Fe(OH)3(s) + e-
S(s) + 2e-
NO3-(ag) + 2H2O + 3e-
NO3 (ag) + H2O + 2e-
ClO4 (ag) + H2O + 2e
O>(g) + 2H20 + 4e-
CIo3 (ag) + 3H20+6e
-0.547
-0.445
Lithium and fluorine ard
ous materials to work
-0.140
NO(g) + 40H-(aq)
NO2 (aq) + 20H-(aq)
ClO, (aq) + 20H-(aq)
→4OH-(aq)
CI-(aq) + 60H-(aq)
CI-(aq) + 20H-(aq)
0.004
0.398
0.401
0.614
0.890
STANDARD
17.2
Increasing strength of oxidizing agents
Increasing strength of reducing agents
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