Which statement regarding these polynomials and their zeros is true? - ○f(x) = (x² − 1) (x + a) has zeros of 1 and -a, only. Of(x) - X3 - ax² + 16x has zeros at 4 and a, only. Of(x) = (x² + 25) (x + a) has zeros of 5 and -a. f(x) = x ³ - 3 - has zeros at 3 and a. ax² - - 16a 9x + 9a

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Which statement regarding these polynomials and their zeros is true?

1. \( f(x) = (x^2 - 1)(x + a) \) has zeros of 1 and \(-a\), only.

2. \( f(x) = x^3 - ax^2 + 16x - 16a \) has zeros at 4 and \(a\), only.

3. \( f(x) = (x^2 + 25)(x + a) \) has zeros of \(\pm 5\) and \(-a\).

4. \( f(x) = x^3 - ax^2 - 9x + 9a \) has zeros at \(\pm 3\) and \(a\).
Transcribed Image Text:Which statement regarding these polynomials and their zeros is true? 1. \( f(x) = (x^2 - 1)(x + a) \) has zeros of 1 and \(-a\), only. 2. \( f(x) = x^3 - ax^2 + 16x - 16a \) has zeros at 4 and \(a\), only. 3. \( f(x) = (x^2 + 25)(x + a) \) has zeros of \(\pm 5\) and \(-a\). 4. \( f(x) = x^3 - ax^2 - 9x + 9a \) has zeros at \(\pm 3\) and \(a\).
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