Which statement is the correct one? a. Comproportionation is a redox reaction in which the oxidation number of an element is simultaneously raised and lowered. Disproportionation is the opposite of comproportionation. a b. Disproportionation is a reaction in which the oxidation number of an element is raised. Comproportionation is a reaction in which the oxidation number of an element is lowered. c. Disproportionation is a redox reaction in which the oxidation number of an element is simultaneously raised and lowered. Comproportionation is the opposite of disproportionation.

Which statement is the correct one? a. Comproportionation is a redox reaction in which the oxidation number of an element is simultaneously raised and lowered. Disproportionation is the opposite of comproportionation. a b. Disproportionation is a reaction in which the oxidation number of an element is raised. Comproportionation is a reaction in which the oxidation number of an element is lowered. c. Disproportionation is a redox reaction in which the oxidation number of an element is simultaneously raised and lowered. Comproportionation is the opposite of disproportionation.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: Use the rules for assigning oxidation number to determine the oxidation states of each atom in the…

A: Oxidation number of alkali metals is always +1 Oxidation number of oxygen is -2. Using these rules…

Q: Indicate the oxidation state of every individual element in the following compounds. Fractional…

A: Oxidation state: It represent that how many electrons are lost and gain by the element in the…

Q: Indicate the oxidation state of every individual element in the following compounds. c. Na,CO3 f.…

A: We have to indicate the oxidation state of every individual element in given compound. We can…

Q: What is the oxidation state of Cr in each compound?a. CrO b. CrO3 c. Cr2O3

A: The given compound is CrO,oxidation state of oxygen = -2.The compound is neutral, no…

Q: Determine the oxidation state of: a. Chlorine in HClO4 b. Manganese in MnO4–2

A: Oxidation number or Oxidation state: • Oxidation number of atoms in pure element or Atoms in free or…

Q: a. Clo; – Clo, b. so - s c. Mn* → MnO,

A: Given a. ClO3=ClO2 b. SO4^-2=S^-2 C. Mn^+2=MnO2 d. Zn=ZnCl2

Q: Determine the oxidation state for each of the elements below. The oxidation state of ... zinc ...…

A: The oxidation state of zinc in zinc hydroxide is

Q: 24. The oxidation number of phosphorous in the phosphate anion, PO43 is; а. -3 b. +3 с. +5 d. -5 e.…

Q: 4. What are the differences between covalent and ionic bonds? With examples of them. 5. What can be…

A: Question 4 - - > The covalent bond is formed between the two atoms by sharing of the electrons…

Q: Indicate the oxidation state of every individual element in the following compounds. Fractional…

A: Oxidation state is a real or imaginary charge which is present on element when it is present in its…

Q: The oxidation state of chlorine in CIO is Select one: O a. -2 ОБ. +2 O c. 0 d. +1 O e. -1

A: Given Molecule = ClO-Oxidation state of chlorine = To be determined

Q: Indicate the oxidation state of every individual element in the following compounds. Fractional…

A: Oxidation state is a number which indicate the number of electrons gained or lost by that element to…

Q: Use the References to access important values if needed for this question. Use the rules (in order)…

Q: iii. Determine the oxidation states of the elements in NaCIO Compound NaCIO Oxidation state of Na…

A: Answer:Formal charge present on an atom in a compound is called its oxidation number in that…

Q: Indicate the oxidation state of every individual element in the following compounds. Fractional…

Q: Which one of the following contains nitrogen in the lowest oxidation state? A.…

A: E. N2H4

Q: Determine the oxidation state for each of the elements below. The oxidation state of chlorine in The…

A: oxidation number, also called oxidation state, the total number of electrons that an atom either…

Q: Write a balanced molecular, ionic and net ionic equation for reaction between: (you must predict the…

A: In the multi subpart questions, we solve only first three subparts according to the Bartleby…

Q: 2[Na→ Nat+e] is a reducing agent equation, and it depicts the oxidation of sodium iron O oxygen O…

A: Since, In oxidation reaction, Oxidation number increases or number of oxygen increases or number of…

Q: What is the equation that you would predict for the reaction of aluminum with hydrogen? a. Al + 3H…

A: Aluminum (Al) is a monoatomic metal with atomic number 13 Al has three valence electrons . Hydrogen…

Q: What is the role of electrons in redox reactions? a.One of the reactants in a redox reaction…

A: Role of electrons in the redox reactions = ?

Q: 4. Build a voltaic cell with one beaker containing a solution of nickel (II) nitrate - Ni(NO3)2 -…

A: Step 1: 4. a. In a voltaic cell, anode is the place where oxidation occurs, there is a loss of…

Q: None

A: Thank you.

Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Which statement is the correct one?
a. Comproportionation is a redox reaction in which the oxidation number of an element is simultaneously
raised and lowered. Disproportionation is the opposite of comproportionation.
a
b. Disproportionation is a reaction in which the oxidation number of an element is raised.
Comproportionation is a reaction in which the oxidation number of an element is lowered.
c. Disproportionation is a redox reaction in which the oxidation number of an element is simultaneously
raised and lowered. Comproportionation is the opposite of disproportionation.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 : Solution :

VIEW

Step 2 : Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Why does lithium hydroxide dissolve in water but aluminum hydroxide does not?
Which one of the following contains nitrogen in the highest oxidation state? A. N2H4 B. HNO2 C. N2 D. NH3 E. NO2
Select all those which have sulfur in a +2 oxidation state OA. SC1₂ OB. SO₂ OC. SO3² OD. SO4² OE. CS₂ OF. SO₂-²
v Question Completion Status: A Moving to another question will save this response. Question 13 Determine the oxidation state of nitrogen in RBNO 2 +2 +3 -4 +5 A Moving to another question will save this response.
Indicate the oxidation state of every individual element in the following compounds. g. SO2 j. Na,SO3 m. SCl,
What is the oxidation state of the carbon indicated by the arrow? OH а. .2 O b.1 O C. O O d. +1 О е. +2
What is the oxidation state of element X in the compound H3X30? a. +3 b. +2 с. +1 d. 0 е. -1 f. -2 g. -3
A) A solution of potassium sulfide is mixed with a solution of magnesium bromide. Identify the two possible products.Choose one or more: A. MgBr B. KBr C. KS D. MgBr2 E. K2Br2 F. K2S G. MgS Part A was solved for.. the correct answers are Bolded. Need help with part B B) Write the formula of the insoluble product from part 1.
For each reaction, indicate which elements are oxidized and which are reduced. a. WO2 + 3H2 → W + 3H20 Oxidized: Reduced: b. 2Na + Cl2 → 2NACI Oxidized: Reduced: C. 2 Fe2O3 + 3C 4Fe + 3CO2 Oxidized: Reduced: