Which property guarantees f:X--->Y is surjective? Of is injective O the preimage of Y is X O f(x)=Y O X=Y

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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**Question: Which property guarantees f: X ---> Y is surjective?**

- ○ f is injective
- ○ the preimage of Y is X
- ○ f(X) = Y
- ○ X = Y

This question pertains to the properties of functions, specifically focusing on the concept of surjectivity. A function \( f: X \to Y \) is surjective if every element in the codomain \( Y \) is the image of at least one element from the domain \( X \). The option that guarantees surjectivity is \( f(X) = Y \). This means that the image of the function \( f \) covers the entire set \( Y \).
Transcribed Image Text:**Question: Which property guarantees f: X ---> Y is surjective?** - ○ f is injective - ○ the preimage of Y is X - ○ f(X) = Y - ○ X = Y This question pertains to the properties of functions, specifically focusing on the concept of surjectivity. A function \( f: X \to Y \) is surjective if every element in the codomain \( Y \) is the image of at least one element from the domain \( X \). The option that guarantees surjectivity is \( f(X) = Y \). This means that the image of the function \( f \) covers the entire set \( Y \).
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