### Educational Exercise: Evaluating Alkenes#### Question:Which one of these depictions of alkenes is **not acceptable** as it has an impossible geometry and/or it is impossible to determine the configuration (e.g., E vs. Z) of the alkene? Select all that apply.#### Alkenes Depictions:1. **Molecule 1:** - Structure: A simple alkene with one CH₃ group and one H atom on each end of the double bond. - Visual Format: Planar layout without any stereochemistry indicators (wedges or dashes).2. **Molecule 2:** - Structure: Contains stereochemical markers with a dashed bond on one side of the double bond and a wedged bond on the opposite side, suggesting conflicting stereochemistry. - Visual Format: Has CH₃ groups, with one depicted using a dashed line, and another using a wedged line on different carbon atoms, leading to potential geometric inconsistencies.3. **Molecule 3:** - Structure: An alkene with stereochemical indicators, one bond is wedged and the other is dashed. - Visual Format: A CH₃ group is shown with a wedged bond on one carbon, and an H with a dashed bond on the other carbon, implying a valid stereochemistry arrangement.4. **Molecule 4:** - Structure: A straightforward depiction with CH₃ and H atoms on opposite sides of the double bond. - Visual Format: No stereochemistry indicators are present, simplifying the interpretation as a planar structure.#### Options:- [ ] 1- [ ] 2- [ ] 3- [ ] 4Carefully analyze each structure and identify which depiction(s) do not conform to correct stereochemical practice or possess geometrical impossibilities. Select the option(s) above that are not acceptable based on the provided alkenes' configurations.

E–Z configuration is the method of describing the absolute stereochemistry of double bonds. To assign E-Z configuration, first of all, we determine the Cahn–Ingold–Prelog priority order of each substituent on a double bond. Then the positions of the higher of the two substituents on each carbon are compared to each other.If the two groups of higher priority are on opposite sides of the double bond, the configuration of the double bond is assigned as E.If the two groups of higher priority are on the same side of the double bond, the configuration is assigned Z.The given structure represents the (Z)-2-butene. In these structures two methyl groups are attached to the opposite side of the double bonds. In the following depictions the E,Z configuration is not possible because the structure of the alkene is drawn incorrectly.The correct option is as follows:

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Which one of these depictions of alkenes is not acceptable as it is an impossible geometry and/or it is impossible to determine the configuration (e.g. E vs. Z) of the alkene? Select all that apply. CH3 H H CH3 CH3 H H X X I b H₂C H₂C H CH3 CH3 1 2 3 4

Which one of these depictions of alkenes is not acceptable as it is an impossible geometry and/or it is impossible to determine the configuration (e.g. E vs. Z) of the alkene? Select all that apply. CH3 H H CH3 CH3 H H X X I b H₂C H₂C H CH3 CH3 1 2 3 4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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