Which of these equations does not represent an oxidation-reduction reaction? O 3AI + 6HCI - 3H2 + AICI3 O 2H20 – 2H2 + O2 O 2Nal + Brz - 2NaBr + 12 O 2NACI + Pb(NO3)2 - PbCl, + 3NANO3 O Cu(NO3)2 + Zn - Zn(NO3)2 + Cu

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**Identifying Oxidation-Reduction Reactions**

Which of these equations does **not** represent an oxidation-reduction reaction?

- ❍ 3Al + 6HCl → 3H₂ + AlCl₃
- ❍ 2H₂O → 2H₂ + O₂
- ❍ 2NaI + Br₂ → 2NaBr + I₂
- ❍ 2NaCl + Pb(NO₃)₂ → PbCl₂ + 3NaNO₃
- ❍ Cu(NO₃)₂ + Zn → Zn(NO₃)₂ + Cu

**Explanation of Reactions:**

1. **3Al + 6HCl → 3H₂ + AlCl₃**
   This is an oxidation-reduction reaction (redox reaction). Aluminum (Al) is oxidized as it loses electrons and hydrogen ions (H⁺) in hydrochloric acid (HCl) are reduced to form hydrogen gas (H₂).

2. **2H₂O → 2H₂ + O₂**
   This differs from a typical redox reaction as it is a decomposition reaction where water (H₂O) decomposes into hydrogen gas (H₂) and oxygen gas (O₂).

3. **2NaI + Br₂ → 2NaBr + I₂**
   This is an oxidation-reduction reaction. Sodium iodide (NaI) is oxidized to sodium bromide (NaBr) while bromine (Br₂) is reduced to iodine (I₂).

4. **2NaCl + Pb(NO₃)₂ → PbCl₂ + 3NaNO₃**
   This is a double displacement reaction and does not involve oxidation and reduction processes. Instead, the ions in the reactants exchange partners to form new compounds.

5. **Cu(NO₃)₂ + Zn → Zn(NO₃)₂ + Cu**
   This is an oxidation-reduction process. Zinc (Zn) is oxidized to form zinc nitrate (Zn(NO₃)₂) and copper (Cu) is reduced from copper nitrate (Cu(NO₃)₂).

Therefore, the correct answer to the question is:

- ❍ 2NaCl + Pb(NO₃)₂ → PbCl₂ + 3NaNO₃
Transcribed Image Text:**Identifying Oxidation-Reduction Reactions** Which of these equations does **not** represent an oxidation-reduction reaction? - ❍ 3Al + 6HCl → 3H₂ + AlCl₃ - ❍ 2H₂O → 2H₂ + O₂ - ❍ 2NaI + Br₂ → 2NaBr + I₂ - ❍ 2NaCl + Pb(NO₃)₂ → PbCl₂ + 3NaNO₃ - ❍ Cu(NO₃)₂ + Zn → Zn(NO₃)₂ + Cu **Explanation of Reactions:** 1. **3Al + 6HCl → 3H₂ + AlCl₃** This is an oxidation-reduction reaction (redox reaction). Aluminum (Al) is oxidized as it loses electrons and hydrogen ions (H⁺) in hydrochloric acid (HCl) are reduced to form hydrogen gas (H₂). 2. **2H₂O → 2H₂ + O₂** This differs from a typical redox reaction as it is a decomposition reaction where water (H₂O) decomposes into hydrogen gas (H₂) and oxygen gas (O₂). 3. **2NaI + Br₂ → 2NaBr + I₂** This is an oxidation-reduction reaction. Sodium iodide (NaI) is oxidized to sodium bromide (NaBr) while bromine (Br₂) is reduced to iodine (I₂). 4. **2NaCl + Pb(NO₃)₂ → PbCl₂ + 3NaNO₃** This is a double displacement reaction and does not involve oxidation and reduction processes. Instead, the ions in the reactants exchange partners to form new compounds. 5. **Cu(NO₃)₂ + Zn → Zn(NO₃)₂ + Cu** This is an oxidation-reduction process. Zinc (Zn) is oxidized to form zinc nitrate (Zn(NO₃)₂) and copper (Cu) is reduced from copper nitrate (Cu(NO₃)₂). Therefore, the correct answer to the question is: - ❍ 2NaCl + Pb(NO₃)₂ → PbCl₂ + 3NaNO₃
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