Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question**: Which of these correctly shows the first step of an S<sub>N</sub>1 reaction mechanism?
**Answer Choices**:
**A)**
- A cyclopentane ring with a bromine (Br) attached to the first carbon.
- Hydroxide ion (HO⁻) is shown attacking the carbon with Br through a curly arrow pointing from the hydroxide to the carbon.
**B)**
- Similar cyclopentane with bromine attached.
- A hydroxide ion indicates a nucleophilic attack at bromine through a curved arrow.
**C)**
- Cyclopentyl carbocation illustrated (positive charge within the ring).
- Hydroxide ion shown with a positive charge, connected through a curved arrow to the carbocation.
**D)**
- Cyclopentyl with bromine.
- Hydroxide ion depicted attacking the carbon directly attached to bromine through a curved arrow.
**E)**
- Displays bromine leaving from the cyclopentane to create a carbocation (indicated by the leaving bromine without any attack).
**F)**
- Cyclopentane with both bromine leaving and hydroxide ion attacking the carbon with Br, along a curved arrow indicating simultaneous attack and leaving.
**Explanation**:
In an S<sub>N</sub>1 reaction, the first step typically involves the leaving group (like bromine) detaching to form a carbocation. Therefore, choice E represents the correct first step where the bromine leaves, resulting in a carbocation formation without a nucleophilic attack occurring simultaneously.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2350e26-7d0e-4bf3-8956-7cf0ee10eb62%2F05e01030-ae58-455f-9c8a-7d6044dce46c%2Fspakmx_processed.png&w=3840&q=75)
Transcribed Image Text:**Question**: Which of these correctly shows the first step of an S<sub>N</sub>1 reaction mechanism?
**Answer Choices**:
**A)**
- A cyclopentane ring with a bromine (Br) attached to the first carbon.
- Hydroxide ion (HO⁻) is shown attacking the carbon with Br through a curly arrow pointing from the hydroxide to the carbon.
**B)**
- Similar cyclopentane with bromine attached.
- A hydroxide ion indicates a nucleophilic attack at bromine through a curved arrow.
**C)**
- Cyclopentyl carbocation illustrated (positive charge within the ring).
- Hydroxide ion shown with a positive charge, connected through a curved arrow to the carbocation.
**D)**
- Cyclopentyl with bromine.
- Hydroxide ion depicted attacking the carbon directly attached to bromine through a curved arrow.
**E)**
- Displays bromine leaving from the cyclopentane to create a carbocation (indicated by the leaving bromine without any attack).
**F)**
- Cyclopentane with both bromine leaving and hydroxide ion attacking the carbon with Br, along a curved arrow indicating simultaneous attack and leaving.
**Explanation**:
In an S<sub>N</sub>1 reaction, the first step typically involves the leaving group (like bromine) detaching to form a carbocation. Therefore, choice E represents the correct first step where the bromine leaves, resulting in a carbocation formation without a nucleophilic attack occurring simultaneously.
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