Which of these correctly shows the first step of an Sy1 reaction mechanism? A) B) Br -Br HO НО Br C) D) ОН НО E) F) -Br Br НО

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Chapter1: Chemical Foundations
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**Question**: Which of these correctly shows the first step of an S<sub>N</sub>1 reaction mechanism?

**Answer Choices**:

**A)**  
- A cyclopentane ring with a bromine (Br) attached to the first carbon.
- Hydroxide ion (HO⁻) is shown attacking the carbon with Br through a curly arrow pointing from the hydroxide to the carbon.

**B)**  
- Similar cyclopentane with bromine attached.
- A hydroxide ion indicates a nucleophilic attack at bromine through a curved arrow.

**C)**  
- Cyclopentyl carbocation illustrated (positive charge within the ring).
- Hydroxide ion shown with a positive charge, connected through a curved arrow to the carbocation.

**D)**  
- Cyclopentyl with bromine.
- Hydroxide ion depicted attacking the carbon directly attached to bromine through a curved arrow.

**E)**  
- Displays bromine leaving from the cyclopentane to create a carbocation (indicated by the leaving bromine without any attack).

**F)**  
- Cyclopentane with both bromine leaving and hydroxide ion attacking the carbon with Br, along a curved arrow indicating simultaneous attack and leaving.

**Explanation**: 
In an S<sub>N</sub>1 reaction, the first step typically involves the leaving group (like bromine) detaching to form a carbocation. Therefore, choice E represents the correct first step where the bromine leaves, resulting in a carbocation formation without a nucleophilic attack occurring simultaneously.
Transcribed Image Text:**Question**: Which of these correctly shows the first step of an S<sub>N</sub>1 reaction mechanism? **Answer Choices**: **A)** - A cyclopentane ring with a bromine (Br) attached to the first carbon. - Hydroxide ion (HO⁻) is shown attacking the carbon with Br through a curly arrow pointing from the hydroxide to the carbon. **B)** - Similar cyclopentane with bromine attached. - A hydroxide ion indicates a nucleophilic attack at bromine through a curved arrow. **C)** - Cyclopentyl carbocation illustrated (positive charge within the ring). - Hydroxide ion shown with a positive charge, connected through a curved arrow to the carbocation. **D)** - Cyclopentyl with bromine. - Hydroxide ion depicted attacking the carbon directly attached to bromine through a curved arrow. **E)** - Displays bromine leaving from the cyclopentane to create a carbocation (indicated by the leaving bromine without any attack). **F)** - Cyclopentane with both bromine leaving and hydroxide ion attacking the carbon with Br, along a curved arrow indicating simultaneous attack and leaving. **Explanation**: In an S<sub>N</sub>1 reaction, the first step typically involves the leaving group (like bromine) detaching to form a carbocation. Therefore, choice E represents the correct first step where the bromine leaves, resulting in a carbocation formation without a nucleophilic attack occurring simultaneously.
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