Which of the following will create a two-dimensional list variable list2D with 3 rows and 2 columns withvalues 0 (Choose all that apply)?list2D[]%3Dfor r in range (3):list2D.append ([])for c in range (2):list2D[r].append (0)[[0, 0],[0, 0],[0, 0]]list2D =O list2D =list2D.append (2* [0])list2D.append (2* [0])list2D.append (2* [0])[]O list2D = []list2D.append (3* [0])list2D.append (3* [0])for r in range(3) :for c in range(2):list2D[r] [c] = 0Next

Given, Python code, to determine which all of them gives list variable with 3 rows and 2 columns…

Which of the following will create a two-dimensional list variable list2D with 3 rows and 2 columns with values 0 (Choose all that apply)? Olist2D %3D for r in range (3) : list2D.append ([]) for c in range (2): list2D[r].append (0) O list2D = [[0, 0], [0, 0], [0, 0]] O list2D = [] list2D.append (2* [0]) list2D.append (2* [0]) list2D.append (2* [0]) O list2D= [] list2D. append (3* [0]) list2D.append (3* [0]) O for r in range (3) : for c in range (2): list2D[r][c] = 0

Which of the following will create a two-dimensional list variable list2D with 3 rows and 2 columns with values 0 (Choose all that apply)? Olist2D %3D for r in range (3) : list2D.append ([]) for c in range (2): list2D[r].append (0) O list2D = [[0, 0], [0, 0], [0, 0]] O list2D = [] list2D.append (2* [0]) list2D.append (2* [0]) list2D.append (2* [0]) O list2D= [] list2D. append (3* [0]) list2D.append (3* [0]) O for r in range (3) : for c in range (2): list2D[r][c] = 0

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

100%

Which of the following will create a two-dimensional list variable list2D with 3 rows and 2 columns with
values 0 (Choose all that apply)?
list2D
[]
%3D
for r in range (3):
list2D.append ([])
for c in range (2):
list2D[r].append (0)
[[0, 0],
[0, 0],
[0, 0]]
list2D =
O list2D =
list2D.append (2* [0])
list2D.append (2* [0])
list2D.append (2* [0])
[]
O list2D = []
list2D.append (3* [0])
list2D.append (3* [0])
for r in range(3) :
for c in range(2):
list2D[r] [c] = 0
Next

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